Answer:
account balance at graduation is 674.17
Step-by-step explanation:
given data
deposit money P = 500
interest rate = 3 % compounded quarterly
we take time period = 10 year ( 2nd grade to 12 grade)
solution
we apply here compound interest formula that is
amount = ..................1
put here value and we get
amount =
amount = 674.174
so account balance at graduation is 674.17
Answer:
$694.63
Step-by-step explanation:
The formula is p(1+r/n)^tn. P, or the principal amount, is 500 dollars. R, or the rate as a decimal, is 0.03. N, or the number of times compounded yearly, is 4. T, or the time in years, is 11, since there are 11 years from grade 2 to grade 12. 12-2+1=11. Now, plug in the information given. 500(1+0.03/4)^4*11 = 500(1.0075)^44 = 694.63 dollars, rounded to the nearest cent.
B) The h(x) values -4,-2,2,4, and 6
C) The h(x) values -5,-4,0,2, and 4
D) -4≤h(x)≤6
Answer:
C
Step-by-step explanation:
Answer:
The probability of finding a sample mean less than 18 hours is 0.0082
Step-by-step explanation:
To find the probability of finding a sample mean less than 18 hours, we need to calculate the z-score of this sample mean 18. And the probability of finding a sample mean less than 18 hours is P(z<z(18)).
Z-score can be calculated as follows:
z(18)= where
Putting the numbers, we get:
z(18)=
Using z- table we can find that P(z<z(18)) = 0.0082
Based on given mean & standard deviation, by using principles of Central Limit Theorem and Z-score calculation, the probability of finding a sample mean less than 18 hours is approximately 0.0082 or 0.82%.
This question is about the probability of a specific sample mean in statistics, based on provided mean and standard deviation values. It requires the principle of the Central Limit Theorem which states that means of samples taken from a population are normally distributed irrespective of the population's distribution.
To answer this question, we first need to calculate the standard error (SE), which is the standard deviation divided by the square root of the sample size (n). In this case, SE = 10/sqrt(144) = 10/12 = 0.83 (rounded to 2 decimal places).
Next, we calculate the Z score, which tells us how many standard deviations an element is from the mean. So, Z = (Sample Mean - Population Mean) / SE = (18 - 20) / 0.83 = -2.4 (rounded to one decimal place).
Using the Z score table (also known as a standard normal distribution table), we find that the probability of a Z value of -2.4 or less is approximately 0.0082. Thus, the probability of finding a sample mean less than 18 hours is 0.0082, or 0.82% when expressed as a percentage.
#SPJ12
Answer: The required equation of the ellipse in standard form is
Step-by-step explanation: We are given to find the equation of an ellipse in standard form with the vertical major axis of length 10 units and minor axis of length 8 units.
Since the major axis is vertical, so it will lie on the Y-axis. Let the standard form of the ellipse be given by
where the length of major axis is 2a units and length of minor axis is 2b units.
According to the given information, we have
and
Substituting the values of a and b in equation (i), we get
Thus, the required equation of the ellipse in standard form is
Complete the table for the given rule.
X Y
0 __
1 __
2 __