the sum of three angles of a triangle adds up to 180 degrees. In this problem, you are given two angles.
x+(2x+15)+the measure of angle Q should equal 180.
Since everything is addition, the parenthesis can be removed.
x+2x+15+Q=180. This can then be simplified to 2x+15+Q=180. Subtract 15 from both sides to get 2x+Q=165. Divide both sides by two to get the x by itself. x+Q=82.5.
Unfortunately I don't really know what to do from here, but I hope it helped at least a little.
2, 3i, -3i are the real and complex solutions of the polynomial equation.
Polynomial is an expression consisting of indeterminates and coefficients, that involves only the operations of addition, subtraction, multiplication, and positive-integer powers of variables
The given polynomial is x³-2x²+9x-18
x³-2x²+9x-18=0
Take the common terms from first two terms
x²(x-2)+9(x-2)
(x²+9)(x-2)=0
(x²+3²)(x-2)=0
x-2=0
x=2
and x²+3²=0
x=3i and x=-3i
Hence, 2, 3i, -3i are the real and complex solutions of the polynomial equation.
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A= B + 3(4-C)
Answer:
A = 11
Step-by-step explanation:
A = B + 3(4 - C) ← substitute B = 5 , C = 2 into the equation
A = 5 + 3(4 - 2) = 5 + 3(2) = 5 + 6 = 11
5: 1, 5
4: 1, 2, 4
21: 1, 21