Answer:
perpendicular
Step-by-step explanation:
it is perpendicular because you flipped and negative the slope. if it was parallel the slope would be the same with no negative
691 648 967 959 826 573 598 790 954
711 515 649 960 949 802 507
a. Construct the frequency distribution using classes of 500 up to 600, 600 up to 700, etc.
Texts Frequency
500 up to 600
600 up to 700
700 up to 800
800 up to 900
900 up to 1000
Total
b. Construct the relative frequency distribution, the cumulative frequency distribution and the cumulative relative frequency distribution. (Round "Relative Frequency" and "Cumulative Relative Frequency" to 2 decimal places.)
Texts Relative Frequency Cumulative Frequency Cumulative Relative Frequency
500 up to 600
600 up to 700
700 up to 800
800 up to 900
900 up to 1000
c-1. How many of the 13-year-olds sent at least 600 but less than 700 text messages?
c-1. Number of 13-year-olds
Number of 13-year-olds
c-2. How many sent less than 900 text messages?
Number of 13-year-olds
d-1. What percent of the 13-year-olds sent at least 800 but less than 900 text messages? (Round your answer to the nearest whole percent.)
Percent of 13-year-olds %
d-5. What percent of the 13-year-olds sent less than 600 text messages? (Round your answer to the nearest whole percent.)
Percent of 13-year-olds %
Answer:
7 ; 19 ; 8% ; 28%
Step-by-step explanation:
Given the data:
791 542 671 672 555 582 616 961 639
691 648 967 959 826 573 598 790 954
711 515 649 960 949 802 507
How many of the 13-year-olds sent at least 600 but less than 700 text messages? = 7
c-2. How many sent less than 900 text messages? = (7 + 7 + 3 + 2) = 19
d-1. What percent of the 13-year-olds sent at least 800 but less than 900 text messages? =0.08 × 100 = 8% (from relative frequency)
d-5. What percent of the 13-year-olds sent less than 600 text messages? 0.28 × 100 = 28% (from relative frequency)
By sorting text messages into classes, we can get the frequency distribution. From there, we can determine the relative and cumulative frequencies. Finally, we can examine how many students sent texts within certain ranges and express these as percentages.
To answer this question, let's first classify the amount of text messages sent by each of the 25 13-year-olds into groups or classes of 100. Then we count the frequencies, or how many text messages fall into each class. This helps us construct the frequency distribution.
The classes are: 500-600, 600-700, 700-800, 800-900, and 900-1000.
Next, we calculate the relative frequency by dividing the frequency of each class by the total number of students. We round each relative frequency to 2 decimal places.
To calculate cumulative frequency, we keep an ongoing total of frequencies as we move up the classes. The cumulative relative frequency is computed similarly but applied to the relative frequencies.
In the last part, we determine how many 13-year-olds sent at least a certain number of texts but less than another number, and convert these to percentages.
#SPJ3
Answer:
C) 35.98
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp /adj
tan 17 = 11/x
x tan 17 = 11
x = 11/ tan 17
x =35.9793788
Answer:
Tjhe final answer I came apon was 35.98 for this problem.
"C) 35.98"
Here why :
First of all it is an
so we can use trigonometry. functions
oppration : tan theta = opp /adj
Step 1 tan 17 = 11/x
Step 2 x tan 17 = 11
Step 3 x = 11/ tan 17
Step 4 x =35.98 (when roundened)
Hope this helps
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Explanation:
We have two workers, more or less. Worker A gets the job done in 5 hours. Worker B comes along to help. If A and B work together, they get the job done in 4 hours. This assumes neither worker hinders the other.
Worker A's rate is 1/5 of a job per hour. In other words, after 1 hour, 1/5 of the job is done.
The combined rate is 1/4 for similar reasoning
Worker B's rate is 1/x where x represents how long it takes worker B to get the job done on its own.
The equation to solve is
1/5 + 1/x = 1/4
Note how 1/5 and 1/x represents the sum of the individual rates to get the combined rate 1/4
To solve this equation, it helps to clear out the fractions. Multiply every term by the LCD 20x
20x(1/5 + 1/x) = 20x(1/4)
20x(1/5) + 20x(1/x) = 20x(1/4)
4x + 20 = 5x
From here you can probably see solving this is relatively easy
4x+20 = 5x
20 = 5x-4x
20 = x
x = 20
Therefore, it will take 20 hours for worker B to get the job done on its own.
Going back to the processing context, it takes 20 hours for the new processor to download the movie. This is where the new processor is working alone without help from the original processor.
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Side note: downloading a movie really depends on internet speed rather than processor speed.
Answer:The fourth option
Step-by-step explanation:
Answer:
The Fourth Answer
Step-by-step explanation:
(4, 19) and (2, 11)
Answer:
General Formulas and Concepts:
Pre-Algebra
Algebra I
Step-by-step explanation:
Step 1: Define
(4, 19)
(2, 11)
Step 2: Find slope m