Answer: 22
Step-by-step explanation:
ground 61 m horizontally from the point of
release.
What is the speed of the ball just before it
strikes the ground?
Answer in units of m/s
The speed of the ball would be 13 m/s just before it strikes the ground.
A ball is thrown horizontally from the top of a 110 m high building. 61 meters horizontally from the moment of release, the ball falls on the earth.
Velocity is defined as the displacement of the object in a given amount of time and is referred to as velocity.
First of all, we get the time of aviation from the vertical component:
Here s = 110 m and g = 9.8 m/s²
s = 1/2 × gt²
Solve for t
t = √(2s/g)
Substitute the values of s = 110 m and g = 9.8 m/s² in the equation,
t = √(2×110/9.8)
t = √22.44
t = 4.7 sec
The horizontal component of velocity is constant :
v = s/t
Here s = 61 m and t = 4.7 sec
v = 61/4.7
v = 12.97 ≈ 13
Therefore, the speed of the ball would be 13 m/s just before it strikes the ground.
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The number of ants after 60 days is 240.
An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.
Example: 2 + 3x + 4y = 7 is an expression.
We have,
The population of ants doubles every 20 days.
Current number of ants = 30
Now,
The number of ants after 20 days.
= 30 x 2
= 60
The number of ants after 40 days.
= 60 x 2
= 120
The number of ants after 60 days.
= 120 x 2
= 240
Thus,
The number of ants is 240.
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lie????
A: 71 and 73
B: 8 and 9
C: 9 and 10
D: 10 and 11