Activity (A) of an element is related to the number of atoms of that element N as follows:
A = k*N --------(1)
k = rate constant = 0.693/t1/2--------(2)
N = # moles of that element * Avogadro's number Na
For Sr: t1/2 = 28.8 yr
A(Sr) = 0.693/28.8 * N(Sr) = 0.0241 * N(Sr)
A(Sr) = 0.0241*(mass Sr/90)*Na= 0.000268 *mass Sr *Na ------------(3)
For Co : t1/2 = 5.26 yr
A(Co) = 0.693/5.26 *N(Co) = 0.1317 *N(Co)
A(Co) = 0.1317 * (1/60)*Na = 0.00219 * Na -------(4)
It is given that:
A(Sr) = A(Co)
0.000268 *mass Sr *Na = 0.00219 * Na
mass Sr = 0.00219/0.000268 = 8.17 g
proton in scientific notation?
Answer:
1.67 ×10^-24g
Explanation:
counting from the first digit after the point till I got to the first non zero digit
Please help
Answer:
Explanation:
1 molecule contains 1 carbon atom.
9.837 * 10^24 molecules contains 9.837 * 10^24 atom of carbon.
It's a 1 to 1 ratio.
Answer:
C) SO3
Explanation:
Lewis formula shows the bonding between atoms of a molecule and expresses the lone pair present in the atoms.
SO3 or Sulfur trioxide cannot be adequately described by a single Lewis formula because it has majorly 3 resonance structures because Sulfur does not follow the octet rule and can expand electrons in its outer shell.
Hence, the correct answer is C) SO3
SO3, or Sulfur Trioxide, is the molecule whose electronic structure requires the depiction of multiple resonance structures for adequate description. The rest of the species can be represented with a single Lewis structure.
The electronic structure that can only be described by drawing two or more resonance structures is SO3 (Sulfur Trioxide). This molecule has 24 valence electrons having a central atom with expanded octet. The Lewis structure is drawn in a way that three resonance structures are needed to represent the bonding in this molecule adequately. On the other hand, the rest of the species given in the options can be described using a single Lewis formula.
#SPJ6
Answer:
Well atomic number 17 is Chlorine, which is most commonly found as a gas, and is period 7.
Explanation:
elements found on period 7 are some of the most unstable elements.
Answer:
1.133 kPa is the average pressure exerted by the molecules on the walls of the container.
Explanation:
Side of the cubic box = s = 20.0 cm
Volume of the box ,V=
Root mean square speed of the of helium molecule : 200m/s
The formula used for root mean square speed is:
where,
= root mean square speed
k = Boltzmann’s constant =
T = temperature = 370 K
M = mass helium =
= Avogadro’s number =
Moles of helium gas = n
Number of helium molecules = N =
N =
Ideal gas equation:
PV = nRT
Substitution of values of T and n from above :
(1 Pa = 0.001 kPa)
1.133 kPa is the average pressure exerted by the molecules on the walls of the container.
The question asks for the average pressure exerted by helium gas molecules on the walls of a cubic container. Using the equation PV = Nmv^2, we can calculate pressure by substituting the given values for volume, number of molecules, mass of one molecule, and root-mean-square speed.
The question is asking to calculate the average pressure exerted by helium gas molecules on the walls of a cubic container. The important formula relating pressure (P), volume (V), number of molecules (N), mass of a molecule (m), and the square of the rms speed (v2) of the molecules in a gas is:
PV = Nmv2,
First, we need to determine the volume of the container, which is the cube of one side, so V = (20 cm)3 = (0.2 m)3. Inserting the given values into the equation and solving for P gives us the desired answer. Recall that the rms speed is given, so no temperature calculations are needed.
Therefore, using all given data points:
Volume (V) = (0.2 m)3
Number of molecules (N) = 2.00 × 1023
Mass of one helium molecule (m) = 3.40 × 10-27 kg
Root-mean-square speed (vrms) = 200 m/s
By substituting these values, we can find the pressure exerted by the gas. This represents an application of kinetic theory of gases which assumes the behavior of an ideal gas.