When an impact causes the car to suddenly change its motion, (D) the people in the car will continue to move in the same direction and at the same speed as before the impact.
Newton's first law of motion states that Unless influenced by an imbalanced force, a body at rest stays at rest, and a body in motion keeps moving in a straight path at a constant pace. This law is commonly known as law of inertia and the resistance of a body to maintain its state of rest is called inertia of rest, same as, the resistance of a body to maintain its state of motion is called inertia of motion.
When a car is moving with certain speed, the car along with the people inside the car is in inertia of motion. In an event of accident, the car comes in rest in no time but the man in the car is still in inertia of motion. So, his body moves forward in the car which may cause injuries. To prevent such injuries, the people inside a car are advised to use safety belts.
So, correct answer is option (D).
Learn more about Newton's first law of motion here:
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Answer:
D :)
Explanation:
Answer:
False
Explanation:
When solutions of different concentration are placed, separated by a semipermeable membrane, the molecules pass from the solution with the lowest concentration of solutes to the one with the highest concentration. This generates a pressure difference on both sides of the semipermeable membrane, called osmotic pressure.
Osmotic pressure is created by the presence of small diffusible molecules that easily move through the capillary membrane. It draws fluid back into the capillaries, opposing hydrostatic pressure.
Osmotic pressure is created by the presence of small diffusible molecules that move through the capillary membrane. It is determined by osmotic concentration gradients, which are the differences in solute-to-water concentrations between the blood and tissue fluid. Osmotic pressure draws fluid back into the capillaries, opposing the hydrostatic pressure that forces fluid out of the capillary.
Osmotic pressure is created by the presence of small diffusible molecules that easily move through the capillary membrane. It draws fluid back into the capillaries, opposing hydrostatic pressure.
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Your vessel's position should be plotted using bearings of fixed known objects on shore.
a. m/s
b. m/s2
c. m2/s
d. kg-m/s2
a. 10N
b. 100N
c. 200N
d. 98N
The smallest value of the force that will make the block not to slide down is 10 N.
We'll begin by calculating the normal reaction. This can be obtained as follow:
N = mg
N = 8 × 10
N = 80 N
Finally, we shall determine the frictional force.
F = μN
F = 0.4 × 80
F = 32 N
Since the frictional force is 32 N, therefore, a force lesser than the frictional force will make the blocknot to slide down.
From the options given above, only option A has a force that is lesserthan the frictional force.
Therefore, the correct answer to the question is Option A. 10 N
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The smallest value of the force that will not slide the 8.0 kg block down the wall is 31.36 N.
To determine the smallest value of the force such that the 8.0 kg block will not slide down the wall, we need to consider the static friction between the block and the wall. The formula for static friction is fs = μs * N, where μs is the coefficient of static friction and N is the normal force. In this case, the normal force is equal to the weight of the block, which is mg = 8.0 kg * 9.8 m/s^2 = 78.4 N. Therefore, the smallest value of the force is equal to the maximum static friction force, which can be calculated as fs = 0.4 * 78.4 N = 31.36 N. So the correct answer is 31.36 N.
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