What relationship do you observe between the temperature and density?

Answers

Answer 1

Answer:

Answer:Density is directly proportional to pressure and indirectly proportional to temperature. As pressure increases, with temperature constant, density increases. Conversely when temperature increases, with pressure constant, density decreases.

Explanation:

hope this helped

Related Questions

What is the difference between a homogeneous and a haterogeneous mixture
Aerial fireworks contain gunpowder and chemicals that produce colors. What elements would be responsible for producing red, green, and yellow colors?
What happens if you don't get nutrients in your body
Which of the following statements explains the difference between a lease and a loan?a. At the end of a loan the car belongs to you, but at the end of a lease, the car still belongs to thelease companyb. At the end of a loan, the car still belongs to the lease company, but at the end of a lease the carbelongs to you.c. A loan requires a large down payment at the beginning while a lease does not.d. A lease requires a large down payment at the beginning while a loan does not.Please select the best answer from the choices provided
Molarity. 0.5 GRAMS of sodium chloride is dissolved to make 0.05 liters of solution. would it be the same as.. 0.5 MOLES of sodium chloride is dissolved to make 0.05 liters of solution? please help me with the grams. thank you (: first time using this!

Fe2O3 + H2 --> Fe + H2OA) what mass of hydrogen gas must be consumed to produe 10.0 g of iron metal?

B) what mass of iron(lll) oxide, Fe2O3, must be consumed to prepare 2.50g of iron metal

Answers

A) 10.0g of Iron is $(10.0)/(55.8)=179mmol$ of Iron.

One mole of dihydrogen is required to form one mole of iron, hence you'll need $0.179*1.00=0.179g$ of dihydrogen.

B) Likewise : 2.50g of Iron is $(2.50)/(55.8)=44.8mmol$ of Iron, hence we'll need $44.8*(3*16+2*55.8)=7.15g$ of Fe2O3.

How many mL of 0.100 m NaHCO3 are needed to prepare 750.0ml of a 0.0500 m NAHCo3 solution

Answers

Following the rule of thumb in dilution, the equation that can be used to solve this problem is:

C1V1 = C2V2

where:
C1 = concentration of solution 1
V1 = volume of solution 1
C2 = concentration of solution 2
V2 = volume of solution 2

(0.1)(V1) = (0.05)(750)
V1 = 375 mL

This shows that 375 mL of a 0.1 m NaHCO3 solution is needed in order to dilute it to a 0.05 m NaHCO3 solution of 750 mL.

A sample of CO2(s) and a sample of CO2(g) differ in their1) chemical compositions
2) empirical formulas
3) molecular structures
4) physical properties

Answers

The correct answer is D.
CO2(s) is a solid.
CO2(g) means it is gas.

So they differ in their physical properties.
Physical propertiers means that they differ in their look.

Which is not a functional group?
a)amino
b)carboxyl
c)halide
d)hydroxyl

Answers

The correct answer is C. Halide is not a functional group. Instead, it is a halogen atom having a negative charge. These halide ions are fluoride, chloride, iodide, astatide and bromide.

Describe a polyhydroxyl alcohol.

Answers

To know that a certain compound is classified as an alcohol is through it molecular equation. Alcohols have at least 1 -OH or hydroxyl attachment. When we say polyhydroxyl that means there is 2 or more hydroxyl group in the structure of an alcohol. Ethylene glycol is an example.

A polyhydroxyl alcohol is an alcohol that has two OH molecules attached. A regular alcohol has only one.

How many dozen of eggs are there in 3500 eggs?

Answers

3500/12 = exactly 291 and 2/3 dozen.

291 & 2/3 dozen are in 3500 eggs

Other Questions

The periodic table is based on an element'sa. atomic number. b. atomic mass. c. molecular size. d. molecular mass.

In the following electrochemical cell, what is the reduction half-reaction? Mn(s) | Mn2+(aq) || Fe3+(aq), Fe2+(aq) | Pt(s)

10.0 grams of a gas occupies 12.5 liters at a pressure of 42.0 mm Hg. What is the volume when the pressure has increased to 75.0 mm Hg? 0.143 L 6.72 L 7.00 L 22.3 L

Do you think the saying “faster, better, cheaper” refers more to the work of a scientist or engineer? Explain