Which number below is a prime number? O A. 39 O B. 105 O c. 101 OD. 15 asap​

Answers

Answer 1
Answer:

Answer:

It should be 101


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Which equation represents a line that passes through (2, –1/2) and has a slope of 3?

Answers

Answer:

Step-by-step explanation:

Let the equation of the line is y = mx + c

where m = slope = 3

and c = y-intercept

Now the equation of this line will become

y = 3x + c

Since this line passes through (2, (-1)/(2))

so  (-1)/(2) = 6 + c

c =  (-1)/(2) - 6

  =  (-13)/(2)

So the line will be y = 3x + (13)/(2)

Hello,

y+1/2=3(x-2)
or y=3x-13/2

Which statement is true for the equation 3x − 3x − 2 = −2?It has no solution.
It has one solution.
It has two solutions.
It has infinitely many solutions.

Answers

Answer:

D. It has infinitely many solutions.

Step-by-step explanation:

We have been given an equation 3x-3x-2=-2. We are asked to find the number of solutions for our given equation.

We know that an equation has infinitely many solutions, when both sides of the equation are equal.

Let us add 3x on both sides of our given equation.

3x-3x+3x-2=-2+3x

3x-2=3x-2

Since both sides of our given equation are equal, therefore, our given equation has infinitely many solutions and option D is the correct choice.

It would come out to 3x = 3x so it would be infinitely many solutions

PLEASE HELP ME SOLVE FOR X

Answers

Answer: 11 I think

Step-by-step explanation:

What is the y-inetrcept of -3x-9y=18

Answers

Simple,

re-write it in y=mx+b for to find your y-intercept..

-3x-9y=18
+3x       +3x

-9y=3x+18
/
-9

y= -(x)/(3) -2

Thus, your y-intercept is, -2.

Can you guys help me please!

Answers

Answer:

Step-by-step explanation:

The scale of a map is 1 cm: 15 km. what is the actual distance corresponding to each map distance

Answers

1km=1,000m\n1m=100cm\ntherefore\n1km=1,000\cdot100cm=100,000cm\n----------------------\n\n15km=15\cdot100,000cm=1,500,000cm\n\n\boxed{1cm:15km\Rightarrow 1cm:1,500,000cm\Rightarrow1:1,500,000}\leftarrow scale\ of\ a\ map\n\n1cm\ of\ the\ map\ is\ equal\ 1,500,000cm\ of\ real\ distance\n1cm\ of\ the\ map\ is\ equal\ 15km\ of\ real\ distance
for every one cm on the map that you measure, you count that as 15 km so if there is a mark 2.5 cm then you count that as 37.5km in real life