8 5/12 divided by 1 3/4
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^fractions lesson^
8 5/12 : 1 3/4
step 1:
(8 × 12 + 5)/12
=101/12
step 2:
(1 × 4 + 3)/4
=7/4
ok, enter:
101/12 : 7/4
=101/12 × 4/7
=404/84
=4 68/84
=4 17/21
Related Questions
Need help will mark Brainliest no explanation needed
Hello, could someone please help me with this
A stone which is dropped into a dry well hits the bottom in 2.2s how deep is the well. take g=10m/s
There were 3 squirrels and 18 acorns on Josh’s back porch. What was the ratio of squirrels to acorns? Enter your answer in reduced form. (100 points!!)
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Answer:
8%
Step-by-step explanation:
Rate = 100×Interest ÷ Principal× Time
100× 2500/ 2500 × 8 = 800
800/100 = 8%
I hope this helps
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Answer:
hello your question has some missing parts below is the missing part
Given below are the analysis of variance results from a Minitab display. Assume that you want to use a 0.05 significance level in testing the null hypothesis that the different samples come from populations with the same mean.
Identify the p-value.
Source DF SS MS F p
Factor 3 13.500 4.500 5.17 0.011
Error 16 13.925 0.870
Total 19 27.425
A) 0.011 B) 4.500 C) 5.17 D) 0.870
answer : p-value = 0.011 ( A )
Step-by-step explanation:
using this information
Source DF SS MS F P
Factor 3 13.500 4.500 5.17 0.011
Error 16 13.925 0.870
Total 19 27.425
significance level = 0.05
given that the significance level = 0.05
and
F statistics are given as : F = 5.17 , F critical = 3.25
hence the p-value = 0.011
from the analysis the p-value is less than the significance level is lower than the significance level
Final answer:
The p-value in a Minitab analysis of variance (ANOVA) test helps determine whether to reject or accept the null hypothesis that the samples all come from populations with the same mean. You would reject the null hypothesis if your p-value is less than the significance level (α = 0.05). Please refer back to your Minitab results to find this p-value.
Explanation:
In the context of your Minitab analysis of variance (ANOVA) results, the p-value that you should be looking at to determine the null hypothesis is not explicitly mentioned in your question. However, based on your description, you want to test the hypothesis that the different samples come from populations with the same mean (null hypothesis).
The p-value represents the probability that you would obtain your observed data (or data more extreme) if the null hypothesis were true. Therefore, if the p-value is less than the significance level (α = 0.05), you would reject the null hypothesis, suggesting that the samples do not all come from populations with the same mean. Conversely, if the p-value is larger than 0.05, you would fail to reject the null hypothesis, suggesting that the samples could come from populations with the same mean.
Please refer back to your Minitab results to find this p-value. Usually, it's labeled in the ANOVA table output as 'P' or 'Prob > F'.
Learn more about p-value here:
#SPJ6
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The amount A resulting from a principal amount P being invested at rate r compounded continuously for time t is given by
... A = P·e^(rt)
FIll in your given values and solve for P.
... 25000 = P·e^(0.0525·12) = P·e^0.63
... P = 25000/e^0.63 ≈ 13314.80 . . . . . divide by the coefficient of P
The amount that must be invested is $13,314.80.
An initial investment (P) compounded continuously with a rate of interest (r) in time (t) will grow to amount (Q) is given by:
Q = P * e^(rt)
Q=25000, r=0.0525, t=12
25000 = P * e^(0.0525*12)
1.8776P = 25000
P = 13314.8
The solution is
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Answer:
Step-by-step explanation:
Formula for average A of two numbers m and n is:
Substitute the value m=36 and n=72
This is equivalent to:
The average is:
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Answer:
No solution
Step-by-step explanation:
add 3 both side
\sqrt{x-4}=-2
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