b. P(A) = 2P(B)
c. P(A) = 1 - P(B)
d. P(A) + P(B) > 1
e. P(A) - P(B) < 0
f. P(A) - P(B) > 1
Answer:
a. P(A) = P(B)
c. P(A) = 1 - P(B)
a and c are true . The rest are false.
Step-by-step explanation:
Two events A and B are said to be equally likely when one event is as likely to occur as the other. In other words each event should occur in equal number in repeated trials. For example when a fair coin is tossed the head is likely to appear as the tail, and the proportion of times each side is expected to appear is 1/2.
So when the events A= {1,3,4} B = {2,4,5} are equally likely then suppose their probability is 1/2.
a. P(A) = P(B) True
1/2= 1/2
b. P(A) = 2P(B) False
1/2 is not equal to 1
c. P(A) = 1 - P(B) True
1/2= 1-1/2= 1/2
d. P(A) + P(B) > 1 False
1/2 + 1/2 is not greater than 1
e. P(A) - P(B) < 0 False
1/2-1/2= 0 is not less than 0
f. P(A) - P(B) > 1 False
1/2-1/2= 0 is not greater than 1
The relationships between the probabilities are evaluated and explained.
a. P(A) = P(B) could possibly hold if P(A) = 1/3 and P(B) = 1/3.
b. P(A) = 2P(B) could not hold, as probabilities cannot exceed 1.
c. P(A) = 1 - P(B) could possibly hold if P(A) = 2/3 and P(B) = 1/3.
d. P(A) + P(B) > 1 could possibly hold if P(A) = 1/3 and P(B) = 1/2.
e. P(A) - P(B) < 0 could not hold, as the difference between probabilities cannot be negative.
f. P(A) - P(B) > 1 could not hold, as the difference between probabilities cannot exceed 1.
#SPJ3
Answer:
$341.00
Step-by-step explanation:
"$ 18.00 each month."
$18.00*$12.00=$216.00
$216.00+$125.00=$341.00
hope this helpes
be sure to give brainliest
B. i^37
C. i^38
D. i^39
Help pleaseee
Answer:
D. i^39
Step-by-step explanation:
If you simplify i^39, you get i^35, i^31, i^27, i^23, i^19, i^15, i^11, i^7, to i^3, which is equal to -i.
Use the best fit line to estimate the distance for a trip that takes 20 minutes.
Enter your response in the box. Give the answer to the tenths place.
miles
Answer:
The anwser is 10.4
Step-by-step explanation:
0.5(20)+0.4
Answer:
(a) less than 10 minutes
= 0.5
(b) between 5 and 10 minutes
= 0.5
Step-by-step explanation:
We solve the above question using z score formula. We given a random number of samples, z score formula :
z-score is z = (x-μ)/ Standard error where
x is the raw score
μ is the population mean
Standard error : σ/√n
σ is the population standard deviation
n = number of samples
(a) less than 10 minutes
x = 10 μ = 10, σ = 2 n = 50
z = 10 - 10/2/√50
z = 0 / 0.2828427125
z = 0
Using the z table to find the probability
P(z ≤ 0) = P(z < 0) = P(x = 10)
= 0.5
Therefore, the probability that the average waiting time waiting in line for this sample is less than 10 minutes = 0.5
(b) between 5 and 10 minutes
i) For 5 minutes
x = 5 μ = 10, σ = 2 n = 50
z = 5 - 10/2/√50
z = -5 / 0.2828427125
= -17.67767
P-value from Z-Table:
P(x<5) = 0
Using the z table to find the probability
P(z ≤ 0) = P(z = -17.67767) = P(x = 5)
= 0
ii) For 10 minutes
x = 10 μ = 10, σ = 2 n = 50
z = 10 - 10/2/√50
z = 0 / 0.2828427125
z = 0
Using the z table to find the probability
P(z ≤ 0) = P(z < 0) = P(x = 10)
= 0.5
Hence, the probability that the average waiting time waiting in line for this sample is between 5 and 10 minutes is
P(x = 10) - P(x = 5)
= 0.5 - 0
= 0.5
Answer:
19.8 or 19 4/5
Step-by-step explanation:
Step 1: Set up the expression.
Step 2: Simplify.
Therefore, the answer is 19.8 or 19 4/5.