Tom has a collection of 30 CDs and Nita has a collection of 18 CDs. Tom is adding 1 CD a month to his collection while Nita is adding 5 CDs a month to her collection Find the number of months after which they 2. will have the same number of CDs.​

The percent increase in vacuum sales from last year to this year is 5%. This means that there was a 5% increase in the number of vacuums sold this year compared to last year's sales.

To calculate the percent increase in vacuum sales from last year to this year, we can use the following formula:

Percent Increase = [(New Value - Old Value) / Old Value] * 100

Where:

New Value = 567 (vacuums sold this year)

Old Value = 540 (vacuums sold last year)

Now, let's plug in the values and calculate:

Percent Increase = [(567 - 540) / 540] * 100

Percent Increase = (27 / 540) * 100

Percent Increase = 0.05 * 100

Percent Increase = 5%

The percent increase in vacuum sales from last year to this year is 5%. This means that there was a 5% increase in the number of vacuums sold this year compared to last year's sales.

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Answer: There's a 3/10th chance its greater than 6.

Step-by-step explanation:

Answer:IQ score≈119.7225

Step-by-step explanation:

To find the IQ score that corresponds to the 90th percentile in a normal distribution with a mean of 100 and a standard deviation of 15, you can use the cumulative distribution function (CDF) of the normal distribution. The CDF gives the probability that a random variable (in this case, IQ) is less than or equal to a specific value.

The formula to find the z-score (standard score) corresponding to a given percentile is:

�

=

invNorm

(

�

)

z=invNorm(p)

Where

�

p is the desired percentile expressed as a decimal (90th percentile would be

�

=

0.90

p=0.90), and

invNorm

invNorm is the inverse normal distribution function.

Then, you can use the z-score to find the IQ score using the formula:

IQ score

=

mean

+

�

×

standard deviation

IQ score=mean+z×standard deviation

Plugging in the given values:

Mean (

mean

mean) = 100

Standard deviation (

standard deviation

standard deviation) = 15

Percentile (

�

p) = 0.90

First, find the z-score:

�

=

invNorm

(

0.90

)

z=invNorm(0.90)

You can use a standard normal distribution table, calculator, or software to find the z-score. For a 90th percentile,

�

≈

1.28155

z≈1.28155.

Now, plug the z-score into the IQ score formula:

IQ score

=

100

+

1.28155

×

15

IQ score=100+1.28155×15

IQ score

≈

119.7225

IQ score≈119.7225

Rounding to the nearest whole number, an IQ score of approximately 120 would place you in the 90th percentile.

Final answer:

To be in the 90th percentile, you would need an IQ score of approximately 119.2.

Explanation:

To find the IQ score corresponding to the 90th percentile, we can use the standard normal distribution table or a calculator. Since the IQ distribution is normally distributed with a mean of 100 and a standard deviation of 15, we can convert the given information into a standard normal distribution by using the formula:

Z = (X - μ) / σ

where Z is the standard score, X is the IQ score, μ is the mean, and σ is the standard deviation.

Since we want to find the IQ score for the 90th percentile, we need to find the Z-score that corresponds to the 90th percentile. From the standard normal distribution table, we find that the Z-score for the 90th percentile is approximately 1.28.

Now, we can solve for X (the IQ score) using the formula:

Z = (X - μ) / σ

Substituting the values, we have:

1.28 = (X - 100) / 15

Solving for X, we get:

X = 1.28 * 15 + 100

Therefore, to be in the 90th percentile, you would need an IQ score of approximately 119.2.

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Answer: yes choice B

Step-by-step explanation:

g(x) has -5 slope

y - g(-1) = -5(x +1)

y -5 = -5x -5

y = -5x

f(x) = xx/2 +2

Xx/2 +2= -5x

Xx/2 +5x +2 = 0

Xx + 10x +4 =0

Solutions: -5 + root(100 -16)/2

And -5 - root(84)/2

Both intersection look like in negative x values