The equation of the composite function is f(h(x)) = 2x-4.
Function composition is an operation ∘ that takes two functions f and g, and produces a function h = g ∘ f such that h(x) = g. In this operation, the functiong is applied to the result of applying the function f to x.
Here, f(x) = x - 7
h(x) = 2x + 3
Now, f(h(x)) = f ( 2x + 3)
= (2x+3)-7
= 2x + 3 -7
= 2x - 4
Thus, the equation of the composite function is f(h(x)) = 2x-4.
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Answer:
Step-by-step explanation:
Write the rule for h(f(x)).
h(f(x)) = 2x - 11
Write the rule for f(h(x)).
f(h(x)) = 2x - 4
Angles of a triangle always add up to 180 degrees. The given angles (90, 90, 20 degrees) give a total of 200 degrees, hence they cannot form a triangle.
In order for three angles to form a triangle, they must satisfy the triangle inequality theorem, which states that the sum of the measures of any two angles in a triangle must be greater than the measure of the third angle.
In this case, you have angles measuring 90 degrees, 90 degrees, and 20 degrees. Let's apply the theorem:
1. Angle 1: 90 degrees
2. Angle 2: 90 degrees
3. Angle 3: 20 degrees
Now, let's check if these angles satisfy the triangle inequality theorem:
- Angle 1 + Angle 2 = 90 degrees + 90 degrees = 180 degrees
- Angle 3 = 20 degrees
According to the theorem, the sum of any two angles must be greater than the measure of the third angle. However, in this case, the sum of Angle 1 and Angle 2 (180 degrees) is not greater than Angle 3 (20 degrees). Therefore, these angles do not satisfy the triangle inequality theorem.
So, the answer is "no," 90 degrees, 90 degrees, and 20 degrees cannot form a triangle because they do not satisfy the triangle inequality theorem.
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Answer:
no. never.
Step-by-step explanation:
total internal angles of a triangle sum to 180. 90 + 90 is 180 so no, you cannot have a triangle with sides 90 90 and 20. it is possiblw to have 90 45 and 45 though
Step-by-step explanation:
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Answer and Step-by-step explanation:
Answer:
The cross section will be an isosceles triangle
Step-by-step explanation:
The image of the inquiry in the joined figure N 1
we realize that
On the off chance that a plane goes through the pivot of revolution of the cone, at that point the resultant cross-area will be a triangle with one vertex as the vertex of the cone and the different sides of the triangle through the vertex A will be equivalent.
Where the base of the triangle will be equivalent to the breadth of the round base of cone and the two compatible sides of triangle will be equivalent to the inclination tallness of the cone
hence
The cross segment will be an isosceles triangle