Which statements are true for the functions g(x) = x2 and h(x) = –x2 ? Check all that apply.For any value of x, g(x) will always be greater than h(x).
For any value of x, h(x) will always be greater than g(x).
g(x) > h(x) for x = -1.
g(x) < h(x) for x = 3.
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x).

Answers

Answer 1
Answer: if x=0 then they have same value

1st and 2nd options are out

for x=-1
g(-1)=1
h(-1)=-1
3rd is true

4th
false

for all values except zero, g(x)>h(x)


correct ones are

g(x) > h(x) for x = -1.
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x).

Answer 2
Answer:

Answer: g(x) > h(x) for x = -1.

For positive values of x, g(x) > h(x).  

For negative values of x, g(x) > h(x).

Step-by-step explanation:

Given functions:g(x)=x^2 and h(x)=-x^2

When x=0, g(0)=0^2=0 and h(0)=-0^2=0

∴ at x=0, g(x)=h(0)

Therefore the statements "For any value of x, g(x) will always be greater than h(x)." and "For any value of x, h(x) will always be greater than g(x)." are not true.

When x=-1, g(-1)=(-1)^2=1 and h(-1)=-(-1)^2=-1

∴g(x) > h(x) for x = -1.  ......................(1)

When x=3, g(3)=(3)^2=9 and h(3)=-(3)^2=--9

g(x) > h(x) for x = 3....................(2)

⇒g(x) < h(x) for x = 3. is not true.

From (1) and (2),

For positive values of x, g(x) > h(x).  

For negative values of x, g(x) > h(x).


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Fall League Soccer & Year

Year & # of Participants

Answers

Year & # Of Participants are the subtitles because fall League Soccer is the title therefore it isn’t a subtitle to the graph :/

Q= 3n +3w solve for n

Answers

n= (Q-3w)/3 when factored

Explain how to use a coordinate plane to find the area of a rectangle with vertices (–4, 9), (–4, –3), (–1, –3), and (–1, 9). what is the area?

Answers

We want to use a coordinate plane to find the area of the given rectangle.

We will see that the area is 36 units squared.

So we only know the vertices of the rectangle, which are:

  • (-4, 9)
  • (-4, -3)
  • (-1, -3)
  • (-1, 9).

The first thing we can do, is graph these in a coordinate axis so we can see our rectangle.

Below you can see the graph of the rectangle where the four vertices are graphed and I drew the sides of the rectangle.

Now that it is graphed is easy to see the measures of each side, one side measures 3 units (from -1 to -4 on the x-value) and the other side measures 12 units (from -3 to 9 on the y-value)

Then the area of the rectangle is:

A = 3*12 = 36 square units.

If you want to learn more about rectangles and areas, you can read:

brainly.com/question/17297081

the formula for area of a rectangle is

Area = length x width

since both the length and the width of the rectangle lie on the same x and y axis, we can find the distance between the width and the distance between the length by subtracting

(-4,9) (-4,-3)

these points lie on the same x axis, so they create a vertical line

9-(-3) = 12

12 units is the distance between them

(-4,-3) (-1,-3)

these points lie on the same y axis, so they create a horizontal line

-1-(-4) = 3

3 units is the distance between them

now that we have the length and the width, we can find the area

A = 12 x 3

A = 36 units²

Please help me this assignment is due todayyy it is 12 points

Answers

Answer:

B

Step-by-step explanation:

the range is the y-values

The range is the Y values, so answer B.

A system of two equations is shown below: Equation C: a = 2b + 7 Equation D: a = 5b − 3 What value of a can be substituted into equation D to solve the system of equations?

Answers

Answer:

C i believe so

Step-by-step explanation:

Answer:

2b + 7

Step-by-step explanation:

i took the test and got it right

I was walking to the store at the same time as my friend Angela. No matter what, She has always gotten there twice as fast as me. Half way to the store her friend picks her up on his scooter which was 10 times faster than me. She got there in 30 minutes. How long did it take for me to get there?

Answers

let's call your speed "a"

her walking speed is then "2a"

and her friend's scooter speed is 10 a

let's also call the distance you need to walk "d"

so the time (t)you need is:

d/t=a
t=d/a

and her time is:
 t=(d)/(2) /2a+ (d)/(2) /10a
(half a distance with the speed of 2a and half a distance (d/2) with the distance of 10 a

now we count (we know that her time is 30 minutes)

30= (d)/(4a)+(d)/(20a) //multiply by 20a

600a= 5d+d
600a=6d/divide by 6
100a=d

Now, in order to calculate your time we need to calculate:

t=d/a

but we know how much is d now!
t=(100a)/(a)=100

which means that you need 100 minutes, or 1 h 40 minutes!!!