MATHEMATICS HIGH SCHOOL

A sequence is defined by the recursive function f(n + 1) = f(n) – 2.If f(1) = 10, what is f(3)?

Answers

Answer 1

Answer: I hope this helps you

Answer 2

Answer:

Answer:

f (3) = 6

Step-by-step explanation:

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Please help me this is geometry and i am so clueless!!!!!

Answers

Answer/Step-by-step explanation:

Problem 1:

E is the centroid of the triangle.

Centroid theorem states that the centroid is ⅔ of the distance of each vertex to the midpoint of the side opposite each vertex.

This implies that:

AE = ⅔(AD)

AE = 21

Therefore:

21 = ⅔(AD)

3*21 = 2(AD)

(3*21)/2 = AD

31.5 = AD

AD = 31.5

Problem 2: Apply the centroid theorem. Thus:

DE = ⅓(AD)

DE = 12

Therefore,

12 = ⅓(AD)

12*3 = AD

36 = AD

AD = 36

On monday morning, there were 30 tickets available for a concert. if 1/3 tickets were sold on monday and 1/5 of those left were sold on tuesday, how many tickets were still available after tuesday's tickets sales? Help please

Answers

1/3 of 30 = 10
30-10= 20
1/5 of 20 = 4
20-4= 16

there were 16 tickets remaining!

I dont have a calculator but i can help you work through it

This problem is kinda hard can you help me

Answers

Answer:

B - 5

Step-by-step explanation:

K: 60

M: 60 x 25%; 60 x .25 = 75

K: 1500/60 = 25

M: 1500/75 = 20

25-20=5

9/35 x 7/16 x 20/21 =

show work

Answers

$(9)/(35)\cdot(\not7^1)/(16)\cdot(20)/(\not21_3)=(9)/(35)\cdot(1)/(\not16_4)\cdot(\not20^5)/(3)=(\not9^3)/(35)\cdot(1)/(4)\cdot(5)/(\not3_1)=(3)/(\not35_7)\cdot(1)/(4)\cdot(\not5^1)/(1)\n\n=(3)/(7)\cdot(1)/(4)\cdot(1)/(1)=(3\cdot1\cdot1)/(7\cdot4\cdot1)=(3)/(28)$

If x=-2f(x) = g(x),
is a solution to the equation
'which of these statements must be true?
The graphs of fand g intersect each other at
X = -2.
The graphs of f and g intersect each other at
X = 2.
-2.
The graphs of fand g intersect the x-axis at
-2.
The graphs of f and g intersect the y-axis at

Answers

Answer: I THINK it’s A

Step-by-step explanation:

Solve simultaneous equation
2x + 4y = 1
3x-5y=7

Answers

$\left \{ {{2x+4y=1\ \ | *(-3)} \atop {3x-5y=7\ \ | *2}} \right. \n\n \left \{ {{-6x-12y=-3} \atop {6x-10y=14}} \right.\n+----\nadd\ both\ equations\n\n-22y=11\ \ \ | divide\ by\ -22\n\ny=-(1)/(2)\n\n2x=1-4y\ \ | divide\ by\ 2\n\nx=(1-4y)/(2)=(1-4*(-(1)/(2)))/(2) =(3)/(2)$

Final answer:

To solve the simultaneous equations 2x + 4y = 1 and 3x - 5y = 7, we can use the elimination method. Multiply the equations to make the coefficients of x equal, subtract the equations, solve for y, and substitute the value of y in one of the original equations to find x. The solution is x = 3/2 and y = -11/22.