PHYSICS HIGH SCHOOL

The wavelength of a given region of the electromagnetic spectrum ranges from 1 x 10-11 - 1 x 10-8 meters. Which waves are found in this region?A) gamma rays

B) x-rays

C) micro waves

D) radio waves

Answers

Answer 1
Answer: Answer: X-rays

The range of X-rays goes from 1x10^-8 to 1x10^-11.

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A suitcase (mass m = 18 kg) is resting on the floor of an elevator. The part of the suitcase in contact with the floor measures 0.50 m × 0.15 m. The elevator is moving upward with an acceleration of magnitude 1.6 m/s2. What pressure (in excess of atmospheric pressure) is applied to the floor beneath the suitcase?

Answers

Answer:

P=2736 Pa

Explanation:

According to Newton we have that:

∑F=m*a\n

A force is exerted by the elevator to the suitcase, according to 3th Newton's law an equal force but in the opposite direction will appeared on the suitcase, that is:

∑F=m*g+m*a=m*(g+a)

F=205.2N

We know that the pressure is given by:

P=(F)/(A)\nP=(205.2N)/((0.50m)*(0.15m))\nP=2736N/m^2=2736Pa

Who experiences MORE force in her glove during a softball game, the catcher or the outfielder? Defend your answer. Use FΔT=mΔv in your explanation.

Answers

The catcher  experiences more force in her glove during a softball game than the outfielder during a softball game.

What is force?

The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. A spring balance can be used to calculate the Force. The Newton is the SI unit of force.

Given that: the equation of motion is:  FΔT=mΔv

Hence, Force = mass × change in velocity/time interval.

Now, during a softball game, the ball is in air more for the outfielder than  the catcher. Hence, from the given equation, the catcher  experiences more force in her glove during a softball game than the outfielder.

Learn more about force here:

brainly.com/question/13191643

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Rich

duPont Manual Highschool

Proffit

Magnesium is a metal that is commonly used in products that needed to be light weight. Suppose a 2.00kg piece of magnesium has 8160 j of entertainment added to it it's temperature increases 4K what is the specific heat of magnesium

Answers

Given that,

Mass of magnesium, m = 2 kg

Heat added to it, Q = 8160 J

Increase in temperature, \Delta T=4\ K

To find,

The specific heat of magnesium.

Solution,

Th formula that is used to find the heat required to raise the temperature in terms of specific heat is given by :

Q=mc\Delta T\n\nc=(Q)/(m\Delta T)\n\nc=(8160\ J)/(2\ kg* 2\ K)\n\nc=2040\ J/kg-K

So, the specific heat of magnesium is 2040\ J/kg-K.

Someone please help on this one?

Answers

so other scientists can see how spread out your data are

Atoms may be bonded together by losing, gaining, or sharing _____________. Question 1 options: A, photons
B. energy
C. electrons
D. neutrons
E. protons

Answers

Answer: Option (C) is the correct answer.

Explanation:

An atom consists of three subatomic particles which are protons, neutrons and electrons.

The protons and neutrons are present inside the nucleus. Whereas electrons revolve around the nucleus.

Whenever there is a bond formed by loss, gain or sharing between any two atoms then it is due to the electrons.

Hence, we can conclude that atoms may be bonded together by losing, gaining, or sharing electrons.
D. neutrons , is fit....

An 81 kg stuntman jumps from the top of a building 29 m above a catching net. Assuming that air resistance exerts a 100 N force on the stuntman as he falls, determine his velocity just before he hits the net

Answers

In order to solve this, we can get all tangled up in acceleration,
or we can just add up the energy budget.

-- Gravitational potential energy = (mass) (grav accel) (height above something)

-- 29 m above the net, his potential energy is (81 x 9.8 x 29) = 23,020 joules

-- All the way down, air resistance exerts 100 N of force against him.
The energy burned up by air resistance is the work done = 100 x 29 = 2,900 joules.

-- The energy he has left when he hits the net is (23,020 - 2,900) = 20,120 joules.

-- When he hits the net, all of his energy is kinetic energy . . . (1/2) (m) (v²)

(1/2) (m) (v²) = 20,120

(40.5) (v²) = 20,120

v² = 20,120 / 40.5

v = square root of (20,120 / 40.5) = 22.3 meters per second (about 50 mph)
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