Answer:
Let x represent the weight of one steel ball. One side will have 8 balls or 8x and the other side will have 14-8 or 6 balls (6x) and the 20 gram weight. 8x = 6x + 20.
The no. of possible solutions is 4 they are (s, e) ⇒ (1, 4), (2, 2), and (4, 1).
A linear equation is an algebraic equation of degree one. In general, the variable or the variables(in the case of a linear equation in two variables) the variables are x and y.
Given, Advance tickets for a school play went on sale.
The price of each student ticket was $4 and everyoneelse paid $5.
's' is the number of student tickets sold, and 'e', is the number of tickets sold to nonstudents and
No more than $80 in tickets were sold.
∴ 4s + 5e ≤ 80.
So, the possible solution are the sum of the multiples of 4 and 5 which results in 80.(only integer values)
4s + 5e ≤ 80.
4s ≤ 80/5e.
Now, when e = 1 , s = 4,
when e = 2 , s = 2,
when e = 4, s = 1.
So, the possible solutions are (1, 4), (2, 2), and (4, 1).
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Answer:
Partial and negative tickets cannot be sold, so the minimum number values of e and s are 0. If s = 0, then e = 16, and if e = 0, then s = 20. Therefore, the values of s are whole numbers from 0 to 20 and the values of e are whole numbers between 0 and 16. The greatest number of student tickets sold was 20 and the greatest number of nonstudent tickets sold was 16.
Step-by-step explanation:
= 1/10 pound x 1/10 pound
= 1/100 pound
= 1 penny
=> 1 pound = 1 penny
How is this possible if 1 pound = 100 pennies