A: 6x^2 - 9x
B: -7x - 8x
C: -7x^2 + 8x
D: 7x + 8x
2. 3k^3(-2k^2 - 4k + 7)
A: -6k^3 - k + 10k
B: -6k^4 - 12k^3 + 21k^2
C: k^4 - k^3 + 10k2
D: 6k^4 - 12k^3 + 10k^2
3. (2k + 1) (k - 4)
A: 2k^2 - 7k + 4
B: 2k^2 - 3k + 4
C: 2k^2 + 9k + 4
D: 2k^2 - 7k - 4
4. (-2y + 5) (y + 3)
A: -2y^2 + 8y + 15
B: -2y^2 - y + 15
C: 2y^2 + 8y + 8
D: 2y^2 - y + 8
Answer: The correct option is (B) negative square root 21 over 5.
Step-by-step explanation: Given that for an angle ,
We are to find the value of
We know that
Cosine is negative in Quadrant II and Quadrant III.
Tangent is positive in Quadrant 1 and Quadrant III.
So, the given angle lies in the Quadrant III.
We will be using the following trigonometric identity:
We have
Since the angle lies in Quadrant III and sine is negative in that quadrant, so
Thus, option (B) is correct.
Answer:
Option B is the correct option.
Step-by-step explanation:
It is given in the question and
We have to calculate the value of
We can see in the figure attached since cos∅ = -2/5
Here negative sign is showing that angle theta is lying either in quadrant 2nd or 3rd.
And is showing as angle is either in quadrant 1 or 3rd.
Therefore it is confirm that angle is lying in quadrant 3 where sine is always negative.
Therefore will be the answer.
3xsquared + 14x +20
A. (- 1, 2)
B. (- 9, 6)
C. (- 2, 7)
D. (6, 3)
E. (1, - 4)
F. (- 7, 0)
Answer:
d b f
Step-by-step explanation: