Explain what happens when you round 4.999 to the nearest tenth?

Answers

Answer 1
Answer: It becomes 5 if you round it to the nearest tenth
Answer 2
Answer: , it becomes 5 ....! tried to help

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Solve the system.x – 2y = 103x + 2y = 14(Points : 5)(–8, 6)(–2, 6)(6, –8)(6, –2)

How do you do this? It's geometry

Answers

45.

12/18 = 8/x <=> 2/3 = 8/x <=> x = (3*8)/2 = 12;

Which of the following sums would be under the radical symbol to find the distance between the points (7, -1) and (-8, -9)?

Answers


Sadly, you didn't put any sums on your list of choices. 
In fact, I can't even find a list of choices !

To find the distance between  (7, -1)  and  (-8, -9),
you would build a sum under a square-root (radical)
symbol, and it would look something like this:

               √ ( 225 + 64 ) .
 

Divide 350 pounds in the ratio 4:2:1

Answers

The problem can be solved by figuring out what "1" represents on the ratio. 350 = 4x+2x+1x (because the problem is asking us to divide it, which means 4x, 2x, and 1x add up to 350).

Then we can  divide 350 by 4+2+1 (7) which equals 50. 

Each "1" is 50, so now we multiply 4 by 50, 2 by 50, and 1 by 50, which equals to 200:100:50. 200+100+50=350.
Hello,

Let's x then common factor of the parts.

part 1: 4*x
part 2: 2*x
part 3: x

So 4x+2x+x=350
==>7x=350
==>x=350/7
==>x=50
Thus
4x=4*50=200
2x=2*50=100
x=50
350=200+100+50

In rhombus ABCD, AB = 2x - 2 and BC = x + 8. Find the length of BCPlease help!!

Answers

AB = BC ;
2x - 2 = x + 8 ;
x = 10 ; 
BC = 18

Marlon asks a friend to think of a number from 5 to 11. What is the probability that Marlon’s friend will think of the number 9?

Answers

Answer:

P=(1)/(7)

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

Let

x---------> size of the event space

y-------> size of the sample space

P=(x)/(y)

In this problem we have

x=1 (because is only one number to think)

y=7 (there are 7 numbers between 5 and 11)

substitute

P=(1)/(7)


There are 7 numbers between 5 and 11 including 5 and 11. This means there is a one in seven chance of any number. The probability of o 9 is 1/7.

Which linear function equation would contain the points below? (-6,-8) and (12,4)

Answers

Answer:

Step-by-step explanation:

The equation of a linear function can be written in the form y = mx + b, where m represents the slope and b represents the y-intercept.

To find the equation of a linear function that contains the points (-6,-8) and (12,4), we first need to find the slope.

The slope (m) can be calculated using the formula:

m = (y2 - y1) / (x2 - x1)

Let's substitute the values from the given points into the formula:

m = (4 - (-8)) / (12 - (-6))

m = (4 + 8) / (12 + 6)

m = 12 / 18

m = 2/3

Now that we have the slope, we can use one of the given points and the slope to find the y-intercept (b).

Using the point (-6, -8), we substitute the values into the equation y = mx + b and solve for b:

-8 = (2/3)(-6) + b

-8 = -12/3 + b

-8 = -4 + b

b = -8 + 4

b = -4

Therefore, the equation of the linear function that contains the points (-6,-8) and (12,4) is y = (2/3)x - 4.

Final answer:

The equation of the linear function that contains the points (-6,-8) and (12,4) is y = (2/3)x - 4.

Explanation:

The linear function equation that contains the points (-6,-8) and (12,4) can be determined by using the slope-intercept form y = mx + b, where m is the slope and b is the y-intercept. First, calculate the slope using the formula m = (y2 - y1) / (x2 - x1). Plugging in the values from the given points, we have m = (4 - (-8)) / (12 - (-6)) = 12/18 = 2/3. Next, choose one of the points to substitute into the equation to find the value of b. Using the point (-6,-8), we have -8 = (2/3)(-6) + b. Solving for b, we get b = -8 + 4 = -4. Therefore, the equation of the line is y = (2/3)x - 4.

Learn more about Linear Function Equation here:

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