How loud is the jetski when the person is 45 feet away?
Answer
7.2593 decibels
Explanation
L ∝ 1/d² Inserting the constant of variation,
L = k/d²
k = Ld²
= 75 × 14²
= 14,700
When d = 45 feet;
L = 14,700/45²
= 14,700/2,025
= 7.2593 decibels
When the person is 45 feet away from the jetski, it is approximately 24.07 decibels loud.
We can use the inverse square law to find how loud the jetski is when the person is 45 feet away. The inverse square law states that the loudness (\(L\)) is inversely proportional to the square of the distance (\(d\)):
We are given that when the person is 14 feet away,. We can use this information to find the value of \(k\):
Now, solve for \(k\):
Now that we have the value of \(k\), we can use it to find the loudness (\(L\)) when the person is 45 feet away:
Plug in the value of \(k\) we found:
Calculate this expression to find the loudness (\(L\)) when the person is 45 feet away:
So, when the person is 45 feet away from the jetski, it is approximately 24.07 decibels loud.
Learn more about inverse square law at brainly.com/question/30562749
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Answer:
The answer to your question is r = 10
Step-by-step explanation:
Data
(x² + 10x ) + (y² - 8y ) = 59
Process
1.- Complete the perfect square trinomials
(x² + 10x + (5)²) + (y² - 8y + (4)²) = 59 + (5)² + (4)²
2.- Simplify
(x² + 10x + 25) + (y² - 8y + 16) = 59 + 25 + 16
3.- Factor
(x + 5)² + (y - 4)² = 100
or (x + 5)² + (y - 4)² = 10²
4.- Compare the result with the standard form
(x - h)² + (y - k)² = r²
then r² = 10²
and r = 10
Answer:
tan theta = -4/3.
Step-by-step explanation:
The inequality means that theta is in the 4th quadrant ( between 270 and 360 degrees.
The angle whose sine is 4/5 is 53.13 degrees.
So the angle whose sine is -4/5 is 306.87 degrees.
The tangent is negative and the triangle formed by the angle in the 4th quadrant has sides 3, - 4 and 5 ( by the Pythagoras theorem).
So tan theta = opposite / adjacent = -4/3 (answer).
Answer:
C. 16
32/8=4 4x4=16
Answer: 30
Step-by-step explanation:
b. 24
c. 29
d. 30