If G(t)=(3t-5)^2 + 4t-1, find each of the following: A.G(a) B.G(a + 2)

Answers

Answer 1

Answer: g(a)=(3a-5)^2+4t-1=9a^2-26x+24
g(a+2)=(3(a+2)-5)^2+4(a+2)-1=9a^2+10x+8

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Which expression finds the measure of an angle that is coterminal with a 300° angle?300° – 860°
300° – 840°
300° – 740°
300° – 720°

Answers

The correct answer is:

300° – 720°

Explanation:

Coterminal angles are angles that, when drawn in standard position, have terminal sides in the same place.

Any angles that are coterminal are some multiple of 360° different in measure. This is because in order to be coterminal, they must travel the entire circle at least once, possibly more times.

Out of the given options, the only one that is a multiple of 360° is 300° – 720° .

The expression that gives an angle that is coterminal with 300 is 300-720. Two angles are said to be coterminal if when they are drawn in a standard position, their terminal sides are on the same location. The expression gives an angle of 420 where when it is drawn the terminal sides are on the same location with the 300.

Oscar is sealing his boat with a special type of sealent. he needs to mix the sealant with water at a ratio of 3:2. How many gallons of water will he need if he planes to use 9 gallons of sealant?

Answers

3/2 9/x . You have to cross Multiplty.

2*9=18
3*x= 3x

18=3x
*Divide 3 from both sides

6=x

log8 (x(x + 6)) = log8 (5x+12)

Please help me!

Answers

As log8(x(x+6)) = log8(5x+12) we can raise e by each side this getting x^2 + 6x = 5x + 12
x^2 + x - 12 = 0
(x+4)(x-3)=0
x=3, x=-4
However we can only do logs of positive number and when -4 is substituted into the equation it gives a negative number so the only true solution is x=3

Please help. i dont understand what i have to do and how to get it. thank you

Answers

Answer:

$\left[\begin{array}{ccc}9\n10\n\end{array}\right]$

Step-by-step explanation:

Evaluate 3a by multiplying each element by 3

3a = 3 $\left[\begin{array}{ccc}2\n4\n\end{array}\right]$ = $\left[\begin{array}{ccc}3(2)\n3(4)\n\end{array}\right]$ = $\left[\begin{array}{ccc}6\n12&\n\end{array}\right]$ , then

3a + b

= $\left[\begin{array}{ccc}6\n12\n\end{array}\right]$ + $\left[\begin{array}{ccc}3\n-2\n\end{array}\right]$ ← sum corresponding elements

= $\left[\begin{array}{ccc}6+3\n12-2\n\end{array}\right]$

= $\left[\begin{array}{ccc}9\n10\n\end{array}\right]$

1. A polyhedron has 6 vertices and 9 edges. How many faces does it have? a. 3
b. 5
c. 7
d. 9
2. A polyhedron has 25 faces and 36 edges. How many vertices does it have?
a. 11
b. 12
c. 13
d. 14

Answers

V - number of vertices,
E - number of edges,
F - number of faces:
Euler`s polyhedron formula:
V - E + F = 2
1. F = E - V + 2
F = 9 - 6 + 2 = 5
Answer: A ) 5
2. V = E - F + 2
V = 36 - 25 + 2 = 13
Answer: C ) 13

Answer: 1. B. 2. C. 3. D. 4. A. 5. A.

For the whole practice test :)

Which equation can be used to find one multiple of 16?

Answers

m(n)=16n where n is a natural number
m(n)=multipules of 16

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