The solution to the expression 1 1/4 × 5 3/5 as a fraction is 4 1/2
from the question, we have the following parameters that can be used in our computation:
1 1/4 × 5 3/5
Convert the fractions to improper fraction
So, we have the following
1 1/4 × 5 3/5 = 5/4 × 18/5
Evaluate the product of the fractions
So, we have the following
1 1/4 × 5 3/5 = 1/4 × 18/1
Simplify
1 1/4 × 5 3/5 = 9/2
So, we have
1 1/4 × 5 3/5 = 4 1/2
Hence, the solution as a fraction is 4 1/2
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Answer:
7
1x4+1/4 x 5 3/5
4+1/4 x 5 3/5
5/4x5 3/5
5/4 x 25+3/5
5/4x38/5
1/4x28
28/4
7
10
14
24
26
b = 10 is the length of leg y of the right triangle.
If a and b are the lengths of the legs of a right-angled triangle and c exists the length of the hypotenuse, then the sum of the squares of the lengths of the legs exists equivalent to the square of the length of the hypotenuse.
Then, the formula exists as
By substituting the value of a, b and c, then we get
b exists missing because we only have one leg
Now consider,
now we remove 676 by 576=100
and it will be
We square root both sides of the equation then we get
b = 10.
Therefore, the correct answer is b = 10.
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The answer is 10 because 24 times 24 is 576 and that plus 100 is 676 and this number squared is 26. 26 is the hypotenuse.
Answer:
Yikes
Step-by-step explanation:
we should private talk in chat. I could explain it to you.
For any value of x, h(x) will always be greater than g(x).
g(x) > h(x) for x = -1.
g(x) < h(x) for x = 3.
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x).
Answer: g(x) > h(x) for x = -1.
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x).
Step-by-step explanation:
Given functions: and
When x=0, and
∴ at x=0, g(x)=h(0)
Therefore the statements "For any value of x, g(x) will always be greater than h(x)." and "For any value of x, h(x) will always be greater than g(x)." are not true.
When x=-1, and
∴g(x) > h(x) for x = -1. ......................(1)
When x=3, and
∴ g(x) > h(x) for x = 3....................(2)
⇒g(x) < h(x) for x = 3. is not true.
From (1) and (2),
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x).