Changing the number of protons in an atom makes

A. an ion
B. an isotope

Answers

Answer 1
Answer: A. an ion

The atom gains a net electrical charge if the number of protons and electrons are not equal which makes it an ion.

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What is the wavelength of a 147-g baseball traveling at 91.0 mph?

Answers

The formula to determine the wavelength is, De-Broglie wavelength formula:

\lambda =(h)/(mv)      -(1)

where, \lambda is wavelength, m is mass, v is velocity and h is Planck's constant = 6.63* 10^(-34) Js = 6.63* 10^(-34) kgm^(2)s^(-1)

mass, m = 147 g  (given)

Since, 1 g = 0.001 kg

So, 147 g = 0.147 kg

v = 91.0 mph    (given)

Converting mph to mps:

Since, 1 mph = (1.609* 10^(3) ms^(-1))/(60* 60)

So, 90 mph = (91* 1.609* 10^(3) ms^(-1))/(60* 60) = 40.67 ms^(-1)

Substituting the values in formula 1:

\lambda =(6.63* 10^(-34) kgm^(2)s^(-1))/(0.147 kg* 40.67 ms^(-1))

\lambda =1.11* 10^(-34) m

Hence, the wavelength wavelength of a 147-g baseball traveling at 91.0 mph is

1.11* 10^(-34) m.


Answer: its D

Explanation:

What medium is the wave traveling through

Answers

Waves can travel through different types of media, such as water and air.

The medium through which a wave travels depends on the type of wave. Mechanical waves require a physical substance for propagation, while electromagnetic waves can travel through both material mediums and empty space due to their unique field-based nature.

The medium through which a wave travels is the substance or material that carries the energy of the wave from one place to another. Waves can propagate through a variety of mediums, and the nature of the medium has a significant impact on the characteristics of the wave.

In mechanical waves, such as sound waves and seismic waves, the medium is typically a material like air, water, or solid objects. In the case of sound waves, air molecules vibrate as the wave passes through, transmitting compressions and rarefactions that our ears perceive as sound. In seismic waves, the Earth's crust and mantle serve as the medium, with rocks transmitting the wave energy.

Electromagnetic waves, like light and radio waves, do not require a physical medium to travel through. They can propagate through a vacuum, such as space, as well as through materials like air, water, and glass. This is because electromagnetic waves consist of oscillating electric and magnetic fields that can interact with charged particles in matter or propagate freely through the vacuum of space.

For more such question on Mechanical waves visit:

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Please Help!!!!!How is the position of the full moon in relation to Earth and the sun different from the position of the full Venus in relation to Earth and the sun? Does the apparent size of the moon change with its phases? Please explain!!!!

Answers

i have got no idea how to answer this question sorry 

Which of these statements explains the relationship among elements, compounds, and mixtures? A. Elements are made of compounds and mixtures. B. Both compounds and mixtures are made up of elements. C. Mixtures are made of elements, and elements are made of compounds. D. Compounds are made of mixtures, and mixtures are made of elements.

Answers

the answer is answer D

Answer:

Its B, both compounds and mixtures are made up of elements.

(5 points) In the lab you find four bags; each contains 5.00 g of a different gas at STP. The gases are O2, C2H6, CO2, and Ne. Which bag has the largest volume?

Answers

Answer:

Ne

Explanation:

Step 1:

Data obtained from the question. This includes:

Mass of O2 = 5g

Mass of C2H6 = 5g

Mass of CO2 = 5g

Mass of Ne = 5g

Step 2:

Determination of the number of mole of each gas:

For O2:

Mass of O2 = 5g

Molar Mass of O2 = 16x2 = 32g/mol

Number of mole of O2 =?

Number of mole = Mass/Molar Mass

Number of mole of O2 = 5/32

Number of mole of O2 = 0.156 mole

For C2H6:

Mass of C2H6 = 5g

Molar Mass of C2H6 = (12x2) + (6x1) = 24 + 6 = 30g/mol

Number of mole of C2H6 =?

Number of mole = Mass/Molar Mass

Number of mole of C2H6 = 5/30

Number of mole of C2H6 = 0.167 mole

For CO2:

Mass of CO2 = 5g

Molar Mass of CO2 = 12 + 16x2 = 12 + 32 = 44g/mol

Number of mole of CO2 =?

Number of mole = Mass/Molar Mass

Number of mole of CO2 = 5/44

Number of mole of CO2 = 0.114 mole

For Ne:

Mass of Ne = 5g

Molar Mass of Ne = 20g/mol

Number of mole of Ne =?

Number of mole = Mass/Molar Mass

Number of mole of Ne = 5/20

Number of mole of Ne = 0.25 mole

Step 3:

Determination of the volume occupied by the each gas.

1 mole of a gas occupy 22.4L at stp.

For O2:

0.156 mole will occupy = 0.156 x 22.4 = 3.49 L

For C2H6:

0.167 mole Will occupy = 0.167 x 22.4 = 3.74 L

For CO2:

0.114 mole Will occupy = 0.114 x 22.4 = 2.55 L

For Ne:

0.25 mole will occupy = 0.25 x 22.4 = 5.6 L

From the calculations made above, Ne has the largest volume

In the reaction, A → Products, the rate constant is 3.6 × 10−4 s−1. If the initial concentration of A is 0.548 M, what will be the concentration of A (in M) at t = 99.2 s? Only enter the numerical value with three significant figures in the answer box below. Do NOT type in the unit (M).

Answers

The value of the concentration of A is 0.529.

Since the rate constant has units of s⁻¹, we can tell that the order of the reaction is 1.

Rate of first -order reaction,

(A)=A_(0) e^(-kt)

Here, A_(0) is the initial concentration, t is the time, A is the final concentration, and k is the rate constant.

Substitute the given value values in the equation as follows,

(A)=0.548M e^{-3.6*10^{-4s^(-1)*99.2s } } \n=0.529M

The concentration of A in (M) is 0.529.

Find more information about first- order reaction here,

brainly.com/question/13309369

     

     

     

Answer:

        \large\boxed{\large\boxed{0.529M}}

Explanation:

Since the rate constant has units of s⁻¹, you can tell that the order of the reaction is 1.

Hence, the rate law is:

       r=d[A]/dt=-k[A]

Solving that differential equation yields to the well known equation for the rates of a first order chemical reaction:

      [A]=[A]_0e^(-kt)

You know [A]₀, k, and t, thus you can calculate [A].

       [A]=0.548M* e^{-3.6\cdot 10^(-4)/s*99.2s}

       [A]=0.529M