[x+y s3
[x+y2-3
Extysa
0
[x+y>3
(x + y <3
(x+y> -3
(x+y<3
Answer:
x + y ≥ 3
x + y ≤ 3
Step-by-step explanation:
In the picture attached, the problem is shown.
The solution to the system:
x + y ≥ 3
x + y ≤ 3
is the line x + y = 3
In order to get a solution to a system of inequalities that is a line, we need the same equation on the left (here, x + y), the same constant on the right (here, 3), and the ≥ sign in one inequality and the sign ≤ in the other one.
The answers are:
3. Addition property of equality
4. - Simplification
7.
To solve the problem, we need to start with the result of the second step:
So,
For the step 3:
Then, for the 3rd step, we have to apply the addition property of equality.
The addition property of equality states that if we add a term to one side of the equality, we need to add it to the other side of the equality, in order to not alterate the equality.
Then, applying the property, we have:
Adding 7 to both sides, we have:
For the step 4:
Now, for the 4th step, we have to simplify the expression:
Then, simplifying, we have:
For the step 7:
Simplificating, we divide each side of the equality by 6:
Have a nice day!
Answer:
Step-by-step explanation:
A circle which has center at point(a,b) on coordinate plane and its radius is r, then its equation is represented by
(x-a)^2 + (y-b)^2 = r^2
______________________________________
In the problem
we have
center as (-3,2) while radius is 2 units.
Thus, it equation can be written based on above discussion as
a = -3, b = 2 r =2
thus, correct choice is option third.
Answer:
5
Step-by-step explanation:
if ax^2 +bx + c ====>discriminant formula is b^2 - 4ac from the quadratic formula
x2 + 3x + 1 = 0
Then;
a=1
b=3
c=1
b^2 - 4ac = 3^2 -4*1*1
= 9-4
= 5