How many times does 36 go into 180

Answers

Answer 1
Answer: It would be 5. Hope this helps. :)
Answer 2
Answer: the answer is 5 hoped that helped

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Using the diagram in #1, which segment(s) are parallel to BC?

Answers

Answer: Segment FE

Step-by-step explanation:

never intesects with segment BC

Blake bought two iced coffees from Dutch Bros. He originally had $13.50 and now has $9. Write and solve an equation to find out how much each icedcoffee cost.

Answers

Answer:

each ice coffee is $2.25

Step-by-step explanation:

13.50 - 9 = 4.50

4.50 / 2 = 2.25

Please help me!! pel​

Answers

Answer:

5

Step-by-step explanation:

plug that bad boy in and chug

(-6)^(2) + 6(-6) +5

36 + (-36) + 5

36 - 36 + 5

5

Answer:

It’s 5

Step-by-step explanation:

Because the new expression would be -6^2 + 6(-6) + 5 then u solve it...

36 + (-36) + 5

which is 5 have a great day!

Assume the population has a normal distribution. A sample of 25 randomly selected students Has a mean test score of 81.5 With a standard deviation of 10.2. Construct a 90% confidence interval for the mean test score.

Answers

Answer:

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of 1 - (1 - 0.9)/(2) = 0.95. So we have T = 2.064

The margin of error is:

M = T(s)/(√(n)) = 2.064(10.2)/(√(25)) = 4.21

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29

The upper end of the interval is the sample mean added to M. So it is 81.5 + 4.21 = 85.71.

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

What is the y-coordinate of the point that divides the directedline segment from J to K into a ratio of 2:3?

K(8,11)

J(-3,1)


*7

*-6

*5

*-5

Answers

Answer:

(D)5

Step-by-step explanation:

Given the point J(-3,1) and K(8,11).

The line segment that divides the segment from J to K in any given ratio can be determined using the formula.

P(x,y)=\left((mx_2+nx_1)/(m+n) ,(my_2+ny_1)/(m+n)\right)

In the given case:

(x_1,y_1)=(-3,1), (x_2,y_2)=(8,11), m:n=2:3

Since we are to determine the y-coordinate of the point that divides JK into a ratio of 2:3, we have:

(my_2+ny_1)/(m+n)=(2*11+3*1)/(3+2)\n\n=(22+3)/(5)\n\n=(25)/(5)\n\n=5

The y-coordinate of the point that divides the directed  line segment from J to K into a ratio of 2:3 is 5.

The correct option is D.

Answer:

The answer is actually C(5) not D

Step-by-step explanation:

The average starting salary of this year's vocational school graduates is $35,000 with a standard deviation of $5,000. Furthermore, it is known that the starting salaries are normally distributed. What are the minimum and the maximum starting salaries of the middle 95% of the graduates

Answers

Answer:

Minimum: $25,200

Maximum: $44,800

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = (X - \mu)/(\sigma)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

\mu = 35000, \sigma = 5000

What are the minimum and the maximum starting salaries of the middle 95% of the graduates

Minimum: 50 - (95/2) = 2.5th percentile.

Maximum: 50 + (95/2) = 97.5th percentile

2.5th percentile:

X when Z has a pvalue of 0.025. So X when Z = -1.96.

Z = (X - \mu)/(\sigma)

-1.96 = (X - 35000)/(5000)

X - 35000 = -1.96*5000

X = 25200

The minimum is $25,200

97.5th percentile:

X when Z has a pvalue of 0.975. So X when Z = 1.96.

Z = (X - \mu)/(\sigma)

1.96 = (X - 35000)/(5000)

X - 35000 = 1.96*5000

X = 44800

The maximum is $44,800