MATHEMATICS HIGH SCHOOL

Mabel measured an angle on her math worksheet with her protractor. The angle measured 39°. If she were to draw an angle which was supplementary to the angle on her worksheet, what should that new angle measure? A. 141° B. 51° C. 129°

Answers

Answer 1

Answer:

The angle supplementary to the angle 39° Mabel measured is C. 129°.

What are supplementary and complementary angles?

When the sum of the two angles is 180° they are said to be supplementary.

When the sum of the two angles is 90° they are said to be complementary.

Given, Mabel measured an angle on her math worksheet with her protractor. The angle measured 39°.

Therefore, The angle supplementary to the angle she measured is,

= (180 - 39)°.

= 129°, As the sum if the sum of two angles are supplementary their sum is

180°.

learn more about supplementary angles here :

brainly.com/question/25251757

#SPJ2

Answer 2

Answer: Supplementary means to be equal to 180 degrees.

180 - 39 = 141

The answer is A. 141 degrees.

Related Questions

ages of edna,ellie and elsa are consequtive integers the sum of their age is 117. their ages are from youngest to oldest. please help.
Steve can complete the hundred meter dash in 10 seconds while Paul can run it in 12 seconds how does Steve's time compared to Paul's
There are 26 baseball teams in the league.Each team has 18 players.Whats a number sentence that will provide a reasonable estimate for the number of players in the league
A catering company charges a $300 set up fee and $10 per person for a lunch buffet. Approximately how many people must attend the lunch so that the total cost per person is $14?
The baseball team has a double-header on Saturday. The probability that they will win both games is 50%. The probability that they will win just the first game is 65%, What is the probability that the team will win the 2nd game given that they have already won the first game?

Find three consecutive even integers whose sum is 36.

Answers

Look at 36/3 = 12.
So let's try 12 along with the one before it and the one after it.

10 + 12 + 14 = 36

yay !

$2n+2n+2+2n+4=36\n 6n=30\n n=5\n\n 2n=2\cdot5=10\n 2n+2=2\cdot5+2=12\n 2n+4=2\cdot5+4=14\n$

If z = -7, what is the value of (-8z) - z?

Answers

Answer:

Step-by-step explanation:

you will plug in -7 for both z's

(-8(-7) - (-7)

following PEMDAS you will do multiplication first

(-8(-7) = 56

now we have 56 - (-7)

since - and - make a positive it will be

56 + 7 = 63

oe is preparing 18 hot dogs for his party. However, Joe only has 12 hot dog buns. How many more hot dog buns does Joe need?*

Answers

Solve:-

18 hot dogs
12 hot dog bun
1 hot dog = 1 hot dog bun

18 - 12 = 6

So, Oe needs 6 more hot dog buns.

he needs 6 more buns

1) Solve by using the perfect squares method. x2 + 8x + 16 = 0 2) Solve. x2 – 5x – 6 = 0

3) What value should be added to the expression to create a perfect square? x2 – 20x

4) Solve. x2 + 8x – 8 = 0

5) Solve: 2x2 + 12x = 0

6) Solve each problem by using the quadratic formula. Write solutions in simplest radical form. 2x2 – 2x – 1 = 0

7) Calculate the discriminant. x2 – x + 2 = 0

8) Calculate the discriminant and use it to determine how many real-number roots the equation has. 3x2 – 6x + 1 = 0

9) Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis. y = 2x2 + x – 3

10) Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis. y = x2 – 12x + 12

Answers

1)
$x^2+8x+16=0 \n(x+4)^2=0 \nx+4=0 \n\boxed{x=-4}$

2)
$x^2-5x-6=0 \nx^2-6x+x-6=0 \nx(x-6)+1(x-6)=0 \n(x+1)(x-6)=0 \nx+1=0 \ \lor \ x-6=0 \nx=-1 \ \lor \ x=6 \n\boxed{x=-1 \hbox{ or } x=6}$

3)
$\hbox{a perfect square:} \n (x-a)^2=x^2-2xa+a^2 \n \n 2xa=20x \n a=(20x)/(2x) \n a=10 \n \n a^2=10^2=100 \n \n \hbox{the expression:} \n x^2-20x+100 \n \n \boxed{\hbox{100 should be added to the expression}}$

4)
$x^2+8x-8=0 \n \na=1 \n b=8 \n c=-8 \n \Delta=b^2-4ac=8^2-4 * 1 * (-8)=64+32=96 \n√(\Delta)=√(96)=√(16 *6)=4√(6) \n \nx=(-b \pm √(\Delta))/(2a)=(-8 \pm 4√(6))/(2 * 1)=(2(-4 \pm 2√(6)))/(2)=-4 \pm 2√(6) \n\boxed{x=-4-2√(6) \hbox{ or } x=-4+2√(6)}$

5)
$2x^2+12x=0 \n2x(x+6)=0 \n2x=0 \ \lor \ x+6=0 \nx=0 \ \lor \ x=-6 \n\boxed{x=-6 \hbox{ or } x=0}$

6)
$2x^2-2x-1=0 \n \na=2 \n b=-2 \n c=-1 \n \Delta=b^2-4ac=(-2)^2-4 * 2 * (-1)=4+8=12 \n√(\Delta)=√(12)=√(4 * 3)=2√(3) \n \nx=(-b \pm √(\Delta))/(2a)=(-(-2) \pm 2√(3))/(2 * 2)=(2 \pm 2√(3))/(2 * 2)=(2(1 \pm √(3)))/(2 * 2)=(1 \pm √(3))/(2) \n\boxed{x=(1-√(3))/(2) \hbox{ or } x=(1+√(3))/(2)}$

7)
$x^2-x+2=0 \n \na=1 \n b=-1 \n c=2 \n\Delta=b^2-4ac=(-1)^2-4 * 1 * 2=1-8=-7 \n \n\boxed{\hbox{the discriminant } \Delta=-7}$

8)
$3x^2-6x+1=0 \n \na=3 \n b=-6 \n c=1 \n \Delta=b^2-4ac=(-6)^2-4 * 3 * 1=36-12=24 \n \n\boxed{\hbox{the discriminant } \Delta=24} \n \n\hbox{if } \Delta\ \textless \ 0 \hbox{ then there are no real roots} \n\hbox{if } \Delta=0 \hbox{ then there's one real root} \n\hbox{if } \Delta\ \textgreater \ 0 \hbox{ then there are two real roots} \n \n\Delta=24\ \textgreater \ 0 \n\boxed{\hbox{the equation has two real roots}}$

9)
$y=2x^2+x-3 \n \n a=2 \n b=1 \n c=-3 \n \Delta=b^2-4ac=1^2-4 * 2 * (-3)=1+24=25 \n \n \hbox{the function has two zeros} \n \boxed{\hbox{the parabola has 2 points in common with the x-axis}} \n \n a\ \textgreater \ 0 \hbox{ so the parabola ope} \hbox{ns upwards} \n \boxed{\hbox{the vertex lies below the x-axis}}$

10)
$y=x^2-12x+12 \n \na=1 \n b=-12 \n c=12 \n \Delta=b^2-4ac=(-12)^2-4 * 1 * 12=144-48=96 \n \n \hbox{the function has two zeros} \n \boxed{\hbox{the parabola has 2 points in common with the x-axis}} \n \n a\ \textgreater \ 0 \hbox{ so the parabola ope} \hbox{ns upwards} \n \boxed{\hbox{the vertex lies below the x-axis}}$

Write an equation of the line with a slope of 2/3
an
and y-intercept of -8.