Two forces, of magnitude 4n and 10n, are applied to an object. the relative direction of the forces is unknown. the net force acting on the object __________.

Answers

Answer 1
Answer:

The net force acting on the object can be either 14 N (if they're in the same direction) or 6 N (if they're in opposite directions).

The net force acting on the object can be determined by considering the vector addition of the two forces. Since the relative direction of the forces is unknown, we need to consider two extreme cases: one where the forces are in the same direction, and the other where they are in opposite directions.

1. Forces in the same direction:

  If both forces are acting in the same direction, their magnitudes simply add up:

  Net Force = 4 N + 10 N = 14 N

2. Forces in opposite directions:

  If both forces are acting in opposite directions, the net force is the difference between their magnitudes:

  Net Force = 10 N - 4 N = 6 N

So, depending on the relative direction of the forces, the net force acting on the object can be either 14 N (if they're in the same direction) or 6 N (if they're in opposite directions).

To learn more about force follow the link:

brainly.com/question/13191643

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Answer 2
Answer:

Final answer:

The net force acting on an object with forces of 4N and 10N, if the direction is unknown, can range from 6N (if forces are opposite) to 14N (if forces are in the same direction).

Explanation:

In physics, the net force acting on an object is the vector sum of all forces acting on it. If the direction of forces is unknown, the net force can be anywhere between the difference (10N - 4N = 6N) and the sum (10N + 4N = 14N) of the magnitudes of the two forces. This is because if the two forces act in the same direction, they add up (resulting in 14N). But if they act in opposite directions, one force will subtract from another (resulting in 6N). If the directions are at an angle, the resultant would be calculated using Pythagoras theorem or trigonometric functions, but we don't have that information from the question.

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the net electric flux through a cube of side 1 m kept in uniform electric field E= 10⁴ N/C î is a. 10⁵ N m² c⁻¹ b. 10⁴ N m² c⁻¹ c. 5 x 10⁴ N m² c⁻¹ d. zero

Answers

Answer:

To calculate the net electric flux through a cube placed in a uniform electric field, you can use Gauss's Law, which states that the electric flux (Φ) through a closed surface is equal to the electric field (E) times the surface area (A) and is also equal to the enclosed charge (Q) divided by the permittivity of free space (ε₀):

Φ = E * A = Q / ε₀

In this case, the cube has a side length of 1 meter, so its surface area (A) is 6 square meters (since there are 6 faces of a cube). The electric field (E) is given as 10⁴ N/C î, and there is no mention of any enclosed charge (Q) within the cube.

Now, calculate the electric flux:

Φ = E * A = (10⁴ N/C) * (6 m²) = 60,000 N m²/C

The unit of electric flux is N m²/C.

So, the net electric flux through the cube is 60,000 N m²/C, which is not one of the provided answer choices. However, if you convert this to the preferred unit of electric flux, which is N m² c⁻¹, you get:

60,000 N m²/C = 60,000 N m² c⁻¹

So, the answer closest to this value is (c) 5 x 10⁴ N m² c⁻¹.

Explanation:

Have great day!

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Answers

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B. Earth
C. Venus
D. Mercury

Answers

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Also, you probably should know, the closer the planet is to the Sun, the faster it revolves around it, therefore it has a shorter year, and since Mercury is the first planet next to Sun it means that Mercury has the shortest year ☺

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Answers

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Answers

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Explanation;

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Answer:

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Explanation:

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Answers

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