How many sides does a convex hexagon have?
a. 4
b. 5
c. 6
d. 7

Answers

Answer 1

Answer: Any hexagon has six sides.

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Select the correct answer. The sum of two numbers is -18. If the first number is 10, which equation represents this situation, and what is the second number? A. The equation that represents this situation is 10 − x = -18. The second number is 28. B. The equation that represents this situation is 10 + x = -18. The second number is -28. C. The equation that represents this situation is x − 10 = -18. The second number is -8. D. The equation that represents this situation is -10 + x = -18. The second number is -8.

Answers

Answer:-28

Step-by-step explanation:

Let A is the second number

the first number is 10.

The total is -18

=> 10 + A =-18 <=> A=-18-10=-28

Solution for x 50=7x-6

Answers

remember you can do anything to an equiaotn aslong as you do it to both sides

try to isolae the variable then find 1 of it

50=7x-6
add 6 to both sides
56=7x
divide both sides by 7
x=8

"Alpha Team, solve the equation!!"
"Roger that, Bravo Team."
.
MISSION OVERVIEW: Isolate the x!!
.
Mission #1: Add 6 on both sides.
.
50+6=7x-6+6
.
56=7x
.
Mission #2: Divide by 7 on both sides.
.
56 / 7 = 7x / 7
.
x = 8.
.
MISSION COMPLETE!!
.
Hope this helped!

Twice a number is added to three times its square. if the result is 16, find the number

Answers

x=2. Honestly, what i did is a guess and check because I wasn't sure. Set up the equation like this. x² + 3(x²)=16 Then just think what makes the most sense and the answer is two because it would end up being 4+3(4) =16 which is correct :)

Which sum or difference identity would you use to verify that cos (180° - q) = -cos q?

Answers

Answer:

$\cos (a-b)=\cos a \cos b+\sin a \sin b$

Step-by-step explanation:

Given : $\cos (180^(\circ)-q)=-\cos q$

We have to write which identity we will use to prove the given statement.

Consider $\cos (180^(\circ)-q)=-\cos q$

Take left hand side of given expression $\cos (180^(\circ)-q)$

We know

$\cos (a-b)=\cos a \cos b+\sin a \sin b$

Comparing , we get, a= 180° and b = q

Substitute , we get,

$\cos (180^(\circ)-q)=\cos 180^(\circ) \cos (q)+\sin q \sin 180^(\circ)$

Also, we know $\sin 180^(\circ)=0$ and $\cos 180^(\circ)=-1$

Substitute, we get,

$\cos (180^(\circ)-q)=-1\cdot \cos (q)+\sin q \cdot 0$

Simplify , we get,

$\cos (180^(\circ)-q)=-\cos (q)$

Hence, use difference identity to prove the given result.

cos (180° - q) = -cos q
First you would use the sum and difference formula of
cos(a – b) = cos(a)cos(b) + sin(a)sin(b) because you have a difference inside the parentheses for cosine.

Hope this helps.

If sin x=0.5, what is the value of cos x?