A regular hexagon has perimeter 60 in. What is the hexagon's area?

Answers

Answer 1

Answer: P = 60 in
P = 6 a
6 a = 60
a = 60 : 6
a = 10 in
The area :
A = 6 · a² √3 / 4
A = 6 · 10² √3 / 4 = 600√3 / 4 = 150 √ 3 in²
Answer:
The hexagon`s area is 150√3 in².

Answer 2

Answer:

Hence, the area of polygon is:

259.8 inches^2.

Step-by-step explanation:

We know that a regular hexagon is a polygon consisting of six equal sides.

Let 'a' be the side length of the hexagon.

We are given perimeter of hexagon=60 in.

This implies.

Perimeter=6a

⇒ 60 =6×a

⇒ a=60/6

⇒ a=10 inches.

Now we know that the area(A) of regular hexagon with side 'a' is given by:

$A=(3√(3))/(2)* a^2$

Now, on putting the value of a we get.

$A=(3√(3))/(2)* (10)^2\n\nA=259.8 \ inches^2$

Hence, the area of polygon is:

259.8 inches^2.

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Answers

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Answers

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