George Westinghouse created a safer and more efficient system for electricity delivery using Alternating Current (AC), which proved superior to Thomas Edison's Direct Current (DC) system.The correct option is C.
The inventor who created a delivery system for electricity that was deemed safer than Thomas Edison's system is George Westinghouse. While Edison's system utilized Direct Current (DC), Westinghouse's approach involved the use of Alternating Current (AC).
This advanced system enabled the delivery of electric power across much farther distances and changed how electricity was used in homes, businesses, and industries.
It led to the expansion of urban areas and allowed factories to operate round-the-clock.
Edison and Westinghouse engaged in a public contention over which system was superior. Despite Edison's efforts to discredit AC power, his method was eventually deemed less efficient, and he had to adapt to the use of AC power due to its growing popularity.
Therefor the correct option is C.
Learn more about Westinghouse's AC Power here:
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Answer: The correct answer is False.
Explanation:
Scientists use the Doppler effect to understand the universe by determining the motion of the object.
Doppler effect: It is the phenomenon in which there is relative motion between the source and listener or source or observer.
Red shift and blue shift can be explained by using the concept of Doppler effect.
From red shift and blue shift, one can conclude that galaxies or stars are moving towards us or going away from us.
The light is shifted to longer wavelength which is red in the case of red shift. The light is shifted to shorter wavelength which is blue in the case of blue shift.
Therefore, "the approximate size of a galaxy can be measured by using the Doppler effect", the given statement is false.
more than 50% but less than 100%
50%
less than 50% but more than 0%
100%
Answer:
50% if light is unpolarized
100% if light is horizontally polarized
0% if light is vertically polarized
Explanation:
A polarizer has an axis that "blocks" the component of light in the direction perpendicular to the direction of the polarizer axis.
When unpolarized light passes through a polarizer, the intensity of light is reduced to , where is the initial intensity of the light: this is because only the component of the light parallel to the axis of the polarizer will pass through, and this component makes 1/2 of the incident light intensity. In this case, since the axis of the polarizer is horizontal, only the horizontal component of the light will pass through, while the vertical component will be blocked. So in this case the final intensity will be 50% of the initial one.
On the other hand, if the incoming light is already horizontally polarized (same orientation as the polarizers), there is no vertical component to block, so all the light passes through the polarizer; therefore, the final intensity will be 100% of the original intensity.
Finally, if the incoming light is vertically polarized, no light will pass through it, because the polarizer's axis is horizontal, so it will block all the vertically polarized light: so the final intensity will be 0% of the original intensity.
All of this is after passing the 1st polarizer; so, after passing the 1st polarizer, the light is now horizontally polarized. Then, the intensity of the light passing through the 2nd polarizer is given by Malus' Law:
where is the angle between the axes of the two polarizers. Since here the two polarizers axes are parallel to each other, , so , and so the intensity after the 2nd polarizer is exactly the same as the intensity after the 1st polarizer.
Answer:
Explanation:
The sensor contains an LDR which has a resistance of 10kohlms in daylight and 100kohlms in the dark.
If the resistor in the circuit is 1 megaohlm, the total resistance in daylight and darkness will be 1.01 megaohms and 1.1 megaohlms.
The percentage difference = (1.1-1.01)/1.1*100% = 8.18%
If the resistor in the circuit is 25 kohlm, the total resistance in daylight and darkness will be 35 kohms and 125 kohlms.
The percentage difference = (125-35)/125*100% = 72%
With the input p.d to the sensing circuit fixed at 12 v, the sensing current will change according to the total resistance. A 72% difference is much more detectable. So the 25 kohm resistor is the better choice.
Answer:
Explanation:
V=IR
I=12/(R of resistor + R of LDR)
R of LDR = 10kohm in light and = 100kohm in dark
R1 = 25kohm
R2 = 1Mohm
solve 4 current
light dark
R1 12/(25+10)=0.343mA 12/(25+100)=0.096mA
R2 12/(1000+10)=0.012mA 12/(1000+100)=0.011mA
so R1 is better as its easier 2 tell its light or dark
Answer: 8 m
Explanation:
From the equation distance = velocity * time, we can find the distance from a velocity vs. time graph by finding the area under the curve, since we get that area from multiplying velocity and time together.
For the first 0.5 seconds, the velocity is 16 m/s and the change in time is 0.5.
16 * 0.5 = 8 m.
Learn more about the relationship between distance and velocity here: brainly.com/question/29409777
We know that there is a formula velocity = frequency x wavelength for all types of waves.
If we assume one complete oscillation of a pendulum to be wavelength we can apply the above formula for the pendulum too.
So as v = fλ and f = v/λ we can just plug in the values to get our answer of frequency.
So frequency = 30/0.35 which is equal to 85.17 Hertz (Hz).
29 million people in the U.S.
Horsepower= 746 W
The above is the info you will need. This is what I have done so far, but it can NOT be right:
98.3*10^15Btu/year(1 year/365 days) = 0.269315*10^15 Btu/day (0.269315*10^15Btu/day)/291 million = (0.2693*10^15 Btu/day)/291*10^6 ~0.00092548109*10^5 Btu/day = 925,481.09Btu/day
925,481.09Btu/day*(1day/24hour) = 38561.71 Btu/hour ~ 38561.7Btu/hour
1horsepower = 746 W
1 W = 3.412Btu/hr38561.7Btu/hr*(1 W/3.412 Btu/hr) ~ 11301.3 W*(1 hp/746 W) = 15.149 hp