MATHEMATICS COLLEGE

HELP LE WITH THE WORKSHEET ITS FOR 6 TH GRADE YALL GOT THIS CMON PLEAE HELPPP ILL GIVE YOU ALL THE POINTS I CAN PLEASE PLEASE PLEASE I BEG

Answers

Answer 1

Answer:

Answer:

1) 55/100

2) 68/100

3) 24/100

4)95/100

5) 72/100

6)44/100

7) 90%

8) 56%

9)35%

10)76%

11) 10%

12)80%

Step-by-step explanation:

Answer 2

Answer:

Answer:

N is 11/20, A is 17/25, T is 6/25, E is 19/20, H is 18/25, I is 11/25, M is 90%, A is 56%, C is 35%, L is 76%, T is 10%, U is 80%

Step-by-step explanation:

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Help a brother out please

Answers

Answer:

Bethlehem has temperatures ranging from 33.8 Fahrenheit to 55.4 Fahrenheit.

Step-by-step explanation:

Hope you got it.

Use the quadratic formula to solve the equation 2y^ +6y-8=0

Answers

To solve this problem you must apply the proccedure shown below:

1. You have the following quadratic equation, which is given in the problem above:

2y^2+6y-8=0

2. So, to solve it, you can use the quadratic formula, which is:

y=(-b±√(b²-4ac))/2a

a=2
b=6
c=-8

3. When you susbtitute these values into the formula, you obtain:

y1=-4
y2=1

The filling variance for boxes of cereal is designed to be .02 or less. A sample of 41 boxes of cereal shows a sample standard deviation of .16 ounces. Use α = .05 to determine whether the variance in the cereal box fillings is exceeding the design specification.

Answers

Answer:

$\chi^2 =(41-1)/(0.02) 0.0256 =51.2$

$p_v =P(\chi^2_(40) >51.2)=0.1104$

In order to find the p value we can use the following code in excel:

"=1-CHISQ.DIST(51.2,40,TRUE)"

If we compare the p value and the significance level provided 0.05 we see that $p_v >\alpha$ so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population variance is not significantly higher than 0.02, so there is no a violation of the specifications.

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

$n=41$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =0.16^2 =0.0256$ represent the sample variance obtained

$\sigma^2_0 =0.02$ represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance specification is higher than the standard of 0.02, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \leq 0.02$

Alternative hypothesis: $\sigma^2 >0.02$

Calculate the statistic

For this test we can use the following statistic:

$\chi^2 =(n-1)/(\sigma^2_0) s^2$

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

$\chi^2 =(41-1)/(0.02) 0.0256 =51.2$

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case $df = 41-1=40$ . And since is a right tailed test the p value would be given by:

$p_v =P(\chi^2_(40) >51.2)=0.1104$

In order to find the p value we can use the following code in excel:

"=1-CHISQ.DIST(51.2,40,TRUE)"

Conclusion

which of the following could be the first step in solving the equation below?5^x=21a. 1/5×5^x=1/5×21b. log5^x=log21c. log5^x=21d. sqrt[5]{ {5}^{x} } = sqrt[5]{21}

Answers

ANSWER

$\log _{}5^x\text{ = log21}$

EXPLANATION

We want to find the very first step in solving the problem below:

$5^x\text{ = 21}$

If we wanted to jump steps, we could just state that the equation would become:

$\log _521\text{ = x}$

But that would be jumping a lot of steps and it is not among the options.

So, the very first step in solving this problem is to find the logarithm of both sides.

That is:

$\log 5^x\text{ = log21}$

That is the answer. (Option B)

There are two spinners containing only black and purple slices.Spinner A has 3 black slices and 12 purple slices.
All the slices are the same size.
Spinner B has 2 black slices and 6 purple slices.
All the slices are the same size.
Each spinner is spun.
List theseſevents from least likely to most likely.
Event 1: Spinner B lands on a black slice.
Event 2: Spinner A lands on a black slice.
Event 3: Spinner B lands on a black or purple slice.
Event 4: Spinner A lands on a green slice.
Least likely
Most likely
Event |
Event |
Event |
Event []

Answers

Answer:

Event 4, Event 2, Event 1, Event 3 (least to most likely)

Step-by-step explanation:

Let's take a look at each event:

Event 1- Spinner B lands on a black slice.

2 black slices, 8 total slices

2/8=1/4=25% probability

Event 2- Spinner A lands on a black slice.

3 black slices, 15 total slices

3/15=1/5=20%

Event 3- Spinner B lands on a black or purple slice.

8 black or purple slices, 8 total slices

8/8=1=100%

Event 4- Spinner A lands on a green slice.

0 green slices, 15 total slices

0/15=0=0%

So, in order of least to most likely, we have Event 4 (0%), Event 2 (20%), Event 1 (25%), and event 3 (100%).

WILL GIVE BRANLIEST!!!! URGENT!!!HELP!!!!! . Find x. A) 3.36 B) 3.3 C) 35.98 D) 38.43

Answers

Answer:

C) 35.98

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp /adj

tan 17 = 11/x

x tan 17 = 11

x = 11/ tan 17

x =35.9793788

Answer:

Tjhe final answer I came apon was 35.98 for this problem.

"C) 35.98"

Here why :

First of all it is an

right triangle,

so we can use trigonometry. functions

oppration : tan theta = opp /adj

Step 1 tan 17 = 11/x

Step 2 x tan 17 = 11

Step 3 x = 11/ tan 17

Step 4 x =35.98 (when roundened)

Hope this helps