Answer:
0.00 J
Explanation:
Answer:
3.43 kPa
Explanation:
Pressure is defined as the ratio between the force applied and the area of the surface on which the force is applied:
in this problem, the force corresponds to the weight of the load, which is given by the product between its mass (350 kg) and the acceleration due to gravity (9.8 m/s^2):
And since the area on which this force is applied is , the pressure exerted on the upper surface of the liquid is
Answer:
The correct answer is we see a Spring tide just after a full moon or no moon phase i.e. twice each lunar month.
Explanation:
A spring tide is popularly known as the "King Tide". As the name suggest, it has nothing to do with the season of spring. It gets its name from the idea of "springing forth". During a spring tide, the tidal range i.e. the difference between high and low water, is maximum. This happens when sun and the moon are on the same side of the earth (new moon) as well as when sun and moon are on the opposite side of the earth (full moon).
Answer: 0.8
Explanation:
The efficiency is defined as the ratio of total imput energy that is actually utilized to the end of the device.
So if we have a total transfer of 1500j of energy, and 1200j are used to heat the thing inside the kettle, 300j are not used to the actual function of the kettle.
So the efficiency is n = 1200j/1500j = 0.8
This means that a 80% of the energy imput is actually used to heat the kettle.
To calculate the efficiency of the kettle, divide the useful output energy (1200 J) by the total input energy (1500 J) and multiply by 100%. This results in an efficiency of 80%, meaning 80% of the energy was converted into useful thermal energy.
In order to find the efficiency of the kettle, we need to compute the ratio of the useful output energy to the total input energy and then multiply by 100% to convert the decimal to a percentage. In this case, the useful output energy is the 1200 J transferred to the thermal energy store. The total input energy is the total energy transferred by the kettle which is 1500 J. So, the efficiency of the kettle is (1200 J / 1500 J) * 100% = 80%.
The remaining 20% energy is wasted and was transferred to the vibrational (sound) energy store, which is a non-useful energy output. An efficient appliance is one which converts a higher proportion of the input energy into useful output energy, with less of it wasted. In this case, 80% of the energy from the kettle was converted into useful thermal energy, hence the kettle is quite efficient.
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