An electrician has a spool of wire that is 200 m long. she needs four pieces of wire measuring 42.3 m, 37.8 m, 55.6 m, and 35.7 m. about how much wire will be left on the spool after she finishes her job? give your answer with the appropriate precision.

Answer:

I would say about 60 to 70 pounds. But I have no more information from you to better answer your question, so that's all I have right now.

Step-by-step explanation:

Answer:

The simplest form would be:

8c² - 1.5d

Explanation:

To simplify an expression, we need to gather the like terms.

Like terms are the ones having the same variable raised to the same power

In the given expression:

6c² + 2.5d - d + 2c² - 3d

We have terms having c² and terms having d.

Therefore, we would gather them as follows:

6c² + 2.5d - d + 2c² - 3d

(6+2)c² + (2.5-1-3)d

8c² - 1.5d ......................> This is the simplest form

Hope this helps :)

Answer: 81.85 km/hr

Converting m/sec into km/hr, 25 m/sec = 90 km/hr

Average =

Time = 50/90  =  5/9 hr

next 120 km at an average speed of 80km/h

=> Time = 120/80  = 3/2  hr

last part of its journey at an average speed of 90km/h in 35 Minutes

time = 35 minutes = 35/60 hr = 7/12 hr

Distance covered = 90 * 7 /12  = 105/2  km

Total Distance = 50 + 120  + 105/2  = 435/2 km

Total time = 5/9 + 3/2 + 7/12   =  ( 20 + 54 + 21) /36  = 95/36

Average speed =   (435/2)/(95 /36)  = 432 * 18  /95 = 81.85 km/hr