The quotient after increased by 4 is 8.
To calculate the quotient of 28 divided by 7, we perform the division and get:
28 ÷ 7
= 28/7
= (7 x 4)/ 7
= 4
Next, we are asked to increase this quotient by 4. Adding 4 to the quotient:
= 4 + 4
= 8.
Therefore, the quotient after increased by 4 is 8.
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Answer:
8 beacaus the seven increased from 4
Step-by-step explanation:
Confidence interval = 90% = 0.90.
1 - 0.90 = 0.10
Mean of 15 batch:
724+718+776+760+745+759+795+756+742+740+761+749+739+747+742 = 11253/15
= 750.2
Mean of second batch:
735+775+729+755+783+760+738+780
= 6055/8
= 756.875
Sd = 20
Z-alpha/2 = 1.64
= (750.2-756.875)-1.64*√20²/15 + 20²/8
= -21.0348
(750.2-756.875)+1.64*√20²/15 + 20²/8
= 7.68
2. The upper limit of the interval is less than 10 so in conclusion the difference in mean batch viscosity is about 10 or less than 10
Answer:
V = π (-2 (ln 2)² + 4 ln 2 − 1)
V ≈ 2.55
Step-by-step explanation:
V = π ∫₁² (1 − (ln x)²) dx
V/π = ∫₁² (1 − (ln x)²) dx
V/π = ∫₁² dx − ∫₁² (ln x)² dx
V/π = x |₁² − ∫₁² (ln x)² dx
V/π = 1 − ∫₁² (ln x)² dx
To evaluate the second integral, integrate by parts.
If u = (ln x)², then du = 2 (ln x) / x dx.
If dv = dx, then v = x.
∫ u dv = uv − ∫ v du
= (ln x)² x − ∫ x (2 (ln x) / x) dx
= x (ln x)² − 2 ∫ ln x dx
Integrate by parts again.
If u = ln x, then du = 1/x dx.
If dv = dx, then v = x.
∫ u dv = uv − ∫ v du
= x ln x − ∫ x (1/x dx)
= x ln x − ∫ dx
= x ln x − x
Substitute:
∫ (ln x)² dx = x (ln x)² − 2 ∫ ln x dx
∫ (ln x)² dx = x (ln x)² − 2 (x ln x − x)
∫ (ln x)² dx = x (ln x)² − 2x ln x + 2x
Substitute again:
V/π = 1 − ∫₁² (ln x)² dx
V/π = 1 − (x (ln x)² − 2x ln x + 2x) |₁²
V/π = 1 + (-x (ln x)² + 2x ln x − 2x) |₁²
V/π = 1 + (-2 (ln 2)² + 4 ln 2 − 4) − (-1 (ln 1)² + 2 ln 1 − 2)
V/π = 1 − 2 (ln 2)² + 4 ln 2 − 4 + 2
V/π = -2 (ln 2)² + 4 ln 2 − 1
V = π (-2 (ln 2)² + 4 ln 2 − 1)
V ≈ 2.55
Answer:
the answer is b
Step-by-step explanation:
Answer: b
Step-by-step explanation:
Answer:
12x7y3
----------- = 6x4y3
6x3y
Step-by-step explanation:
In dividing these numbers, you simply subtract 6x from 12x and subtract 3y from 7y because 6x and 3y are both in the denominator. 3 is left alone.
9514 1404 393
Answer:
B, D, E
Step-by-step explanation:
Any of the following will put rectangle 1 on top of rectangle 2:
Answer:
Answer is B
Step-by-step explanation:
If you are unsure about where to start, you could always plot some numbers down until you see a general pattern.
But a more intuitive way is to determine what happens during each transformation.
A regular y = |x| will have its vertex at the origin, because nothing is changed for a y = |x| graph. We have a ray that is reflected at the origin about the y-axis.
Now, let's explore the different transformations for an absolute value graph by taking a y = |x + h| graph.
What happens to the graph?
Well, we have shifted the graph -h units, just like a normal trigonometric, linear, or even parabolic graph. That is, we have shifted the graph h units to its negative side (to the left).
What about the y = |x| + h graph?
Well, like a parabola, we shift it h units upwards, and if h is negative, we shift it h units downwards.
So, if you understand what each transformation does, then you would be able to identify the changes in the shape's location.
Answer:
answer is b
Step-by-step explanation:
because i got it right on E D G E