Find the mD
55
35
В

Answers

Answer 1
Answer: Not answere just need point srry

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The graph of f(x) = x2 was transformed to create the graph of g(x) = (x − 7.5)2. Which of these describes this transformation?A. A horizontal shift to the right 7.5 unitsB. A horizontal shift to the left 7.5 unitsC. A vertical shift down 56.25 unitsD. A vertical shift up 56.25 units
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I need help please!!

Answers

Answer:

2 remainder 5 ily

Step-by-step explanation:

WILL MARK BRAINLIEST PLEASE HELP!!!A right circular cone is intersected by a plane that passes through the cone's vertex and is parallel to its base, as in the picture below. What is produced from this intersection?

A. A Pair of intersecting lines
B. A Parabola
C. A Point
D. A Pair of parallel lines

Answers

Answer:its D. A pair of parallel lines

Step-by-step explanation:

Answer: parallel lines

Step-by-step explanation:

Use the technique developed in this section to solve the minimization problem. Minimize C = −3x − 2y − z subject to −x + 2y − z ≤ 20 x − 2y + 2z ≤ 25 2x + 4y − 3z ≤ 30 x ≥ 0, y ≥ 0, z ≥ 0 The minimum is C = at (x, y, z) = .

Answers

Answer:

C= -145, (35/4, 295/8, 45)

Step-by-step explanation:

Use Gaussian elimination to find the values of x, y and z

Eq 1: -x+2y-z=20

Eq 2: x-2y+2z=25

Eq 3: 2x+4y-3z=30

  • Multily Eq1 by 1 and add to Eq 2

Eq 1: (-x+2y-z=20 ) × 1

Eq 2:  x-2y+2z=25

Eq 3:  2x+4y-3z=30

⇒ Eq1: -x+2y-z=20

    Eq2:         z= 45

   Eq 3: 2x+4y-3z=30

  • Multiply Eq 1 by 2 and then add to Eq 3

Eq1:  (-x+2y-z=20 ) × 2

Eq2:            z= 45

Eq3:   2x+4y-3z=30

⇒ Eq1:  -x+2y-z=20

   Eq2:            z= 45

  Eq3:      8y-5z= 70

  • swap Eq 2 and Eq 3

Eq 1: -x+2y-z=20

Eq 3:     8y-5z= 70

Eq 2:       z= 45

  • Solve Eq 2 for z

Z=45

  • solve Eq Eq 3 for y.

y= 295/8

  • Using the value z=45 and y= 295/8, substitue in Eq 1 to get value of x

x= 35/4

  • Substitue values of x,y and z in C= -3x-2y-z to get minimum value of C

C= -145

1) Which number line belowshows x 4?
a)
1 2 3 4 5 6
b)
0 1 2 3 4 5 6

C)26
O i 2 3 4
D)5
0 1 2
3 4 5
6
A
B
оооо
С
D

Answers

It’s c i think or can be d but my best bet is c !!

WILL GIVE BRAINLIESTThe graph below represents which system of inequalities? (attachment below)

A. y ≤ −2x + 3
y ≤ x + 3

B. y ≥ −2x + 3
y ≥ x + 3

C. y ≤ −3x + 2
y ≤ −x + 2

D. y > −2x + 3
y > x + 3

Answers

The answer is A.
We can first eliminate D since it uses these (<, >) signs and the lines are shaded, indicating the points on those lines are solutions.
We can also eliminate C because the y intercept in C’s lines is 2, while in the graph, they are both 3.
Finally, we can look at both inequalities on the graph and see that the shaded areas are both underneath the line. This means that y is less than the equation for the line, eliminating B
So, the answer is A
Hope this made sense!!

An ordinary regression model that treats the response Y as normally distributed is a special case of a GLM, with normal random component and identity link function. 1. With a GLM. Y does not need to have a normal distribution and one can model a function of the mean of Y instead of just the mean itself, but In order to get the maximum likelihood estimates the variance of Y must be constant at all values of predictors. ii. The Pearson residual e_inty_i-muhatiysqrt(muhat_) for a GM has a large-sample standard normal distribution (a)) True False, (w) True; (b)) True 00 True True (co False 0 false, Oll) False; IdFalse 00 True (1) False;

Answers

An ordinary Regression model that treats the response Y is (a) True False, (w) True

What is Regression?

A statistical method called regression links a dependent variable to one or more independent (explanatory) variables.

A regression model can demonstrate whether changes in one or more of the explanatory variables are related to changes in the dependent variable.

A) Models for numerical response variable, like ANOVA and linear regression are special cases of GLMs

for these model the following holds

1. Random component has a normal distribution

2. Systematic component α+β₁x₁+β₂x₂+...........βₓxₓ

3. link function = identity (g(µ)=µ)

GLMs can generalise these models with response Y as normally distributed, hence the statement is True

B) With a GLM. Y does not need to have a normal distribution and one can model a function of the mean of Y instead of just the mean itself. but in order to get ML estimates the variance of Y must be small. This small variance of Y is the reason for ML estimator to be the best one. hence the statement is false.

An ordinary Regression model that treats the response Y is (a) True False, (w) True

To learn more about Regression Visit:

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