5 years ago, Cheryl was d years old, Brandon is 2 years older than Cheryl.a. how old is Cheryl

b. how old is Brandon

c. what was the difference in their ages 5 years ago?

d. what is the sum of their ages now?

e. what will the sum of their ages be two years from now?

f. what will the difference of their ages be two years from now

will mark the brainliest.

Answer:

18

Step-by-step explanation:

a) The given equation using the information as it is given above that can be solved to answer this problem is 4r + 4(r+3) = 68

b) The speed of both cyclists are 3mi/hr and 10mi/hr respectively

The formula for calculating the distance covered is expressed as:

Distance = speed * time

Let the speed covered by one cyclist be t

If one cycles 3 miles per hour faster than the other, the speed of the other will be t + 3

If both meet after 4 hours of riding, then their time will be 4 hours

Distance covered the first cyclist = 4r

Distance covered by the second = 4(r+3)

If the two cyclists are 68 miles apart, then:

4r + 4(r+3) = 68

a) The given equation using the information as it is given above that can be solved to answer this problem is 4r + 4(r+3) = 68

b) Expand the equation in a to get "r"

4r + 4r + 12 = 68

8r + 12 = 68

8r = 68 - 12

8r = 56

r = 56/8

r = 7miles per hour

Speed of the first cyclist = 7mi/hr

Speed of the second cyclist = 3 + 7mi/hr = 10mi/hr

Hence the speed of both cyclists are 3mi/hr and 10mi/hr respectively

Learn more here: brainly.com/question/19915685

Answer:

4r + 4(r + 3) = 68

r = 7 miles per hour

r + 3 = 10 miles per hour

Step-by-step explanation:

distance = rate * time

a)

4r + 4(r + 3) = 68

Distribute

4r + 4r + 12 = 68

8r + 12 = 68

8r = 56

r = 7 miles per hour

r + 3 = 10 miles per hour

Answer:

50%

Step-by-step explanation:

The circle is split into 4 parts and there are 2 parts of the circle shaded.

Step 1:

2/4 = 50/100

Step 2:

50/100 = 50%

Answer:

50%

Hope This Helps :)

Answer:

x=2.5+sqrt(300)/4, 2.5-sqrt(300)/4

Step-by-step explanation:

1. Need to factor or can use the quadratic formula

2x^2-10x-3=0

a=2, b=-10, c=-3

[-b+-sqrt(b^2-4*a*c)]/(2*a)

[10+-sqrt(100-4*(-200)]/4

[10+- sqrt(300)]/4

x=2.5+sqrt(300)/4, 2.5-sqrt(300)/4