Answer: Save it
Step-by-step explanation:
(a) A + B: The result is -4i - 6j, with a magnitude of 2√13 and a direction angle of arctan(3/2).
(b) A - B: The result is -2i + 6j, with a magnitude of 2√10 and a direction angle of arctan(-3).
The given vectors are:
B = -i - 4j
A = -3i - 2j
(a) A + B:
To add two vectors,
Simply add their corresponding components.
So, A + B = (-3i - 2j) + (-i - 4j)
Combining the i-components, we get:
-3i - i = -4i.
And combining the j-components, we get:
-2j - 4j = -6j.
Therefore, A + B = -4i - 6j.
To find the magnitude of A + B,
Use the Pythagorean theorem:
|A + B| = ,
Where x is the magnitude of the i-component and y is the magnitude of the j-component.
In this case,
x = -4 and y = -6,
So: |A + B| =
|A + B| = 2√13
To find the direction angle of A + B,
Use the arctan function:
θ = arctan(y / x),
Where y is the j-component and x is the i-component.
In this case,
x = -4 and y = -6,
so: θ = arctan(-6 / -4)
θ = arctan(3/2)
Therefore, the magnitude of A + B is 2√13 and the direction angle is arctan(3/2).
(b) A - B:
To subtract two vectors,
Subtract their corresponding components.
So, A - B = (-3i - 2j) - (-i - 4j).
Combining the i-components, we get:
-3i + i = -2i.
And combining the j-components, we get:
-2j - (-4j) = 2j + 4j = 6j.
Therefore, A - B = -2i + 6j.
To find the magnitude of A - B,
Use the Pythagorean theorem:
,
Where x is the magnitude of the i-component and y is the magnitude of the j-component.
In this case,
x = -2 and y = 6,
so:
|A - B| = 2√10
To find the direction angle of A - B,
Use the arctan function:
θ = arctan(y / x),
Where y is the j-component and x is the i-component.
In this case, x = -2 and y = 6,
so:
θ = arctan(6 / -2)
θ = arctan(-3)
Therefore,
The magnitude of A - B is 2√10 and the direction angle is arctan(-3).
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The complete question is:
For vectors B =−i −4j and A =−3i −2j ,
Calculate (a) A + B and its magnitude and direction angle, and (b) A − B and its magnitude and direction angle.
The resulting vectors after adding and subtracting vectors A and B are A + B = -4i - 6j with a magnitude of 7.21 and A - B = -2i + 2j with a magnitude of 2.83. The direction angle for the vectors are calculated using arctan of the absolute value of the components' ratios.
For vectors B = -i - 4j and A = -3i - 2j, you first need to add and subtract these vectors component-wise to get the resulting vectors. Addition gives A + B = -i + (-3i) + -4j + (-2j) = -4i - 6j, whereas subtraction gives A - B = -3i - (-i) + -2j - (-4j) = -2i + 2j.
The magnitude of a vector is calculated by the Pythagorean theorem: (magnitude of A+B) = sqrt((-4)^2 + (-6)^2) = 7.21 and (magnitude of A-B) = sqrt((-2)^2 + 2^2) = 2.83.
The direction angle is found using arctan(|Ay / Ax|), but adjustment must be made depending on the quadrant of the resulting vector. In conclusion, (a) A + B = -4i - 6j, |A + B| = 7.21, angle = arctan(6/4), and (b) A - B = -2i + 2j, |A - B|= 2.83, angle = arctan(2/2).
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Answer:
The answer to your question is: 1
Step-by-step explanation:
Data
114%
Process
63 mg
6.3 g
0.63 kg
Answer: 6.3 g
Step-by-step explanation:
First, we need to put every mesure into the same unit. Let's put all into grams.
- kg would be too heavy for a quarter (consider that we use kg to weight people, for example)
- mg is too light (consider that we use mg to weight pills, for example)
We know that
1 kg = 1000 g
1 g = 1000 mg
630 g = 630 g
63 mg = 63/1000 = 0.063 g
6.3 g = 6.3 g
0.63 kg = 0.63*1000 = 630 g
The most suitable answer for a quarter is 6.3g, because 630 g would be too heavy and 0.063 g would be too light.
2) When there is no object on the spring, its length 15.5 cm
3) For every ounce of weight, the spring length increases by 2.3 cm
4) For every ounce of weight, the spring length increases by 1535 cm