Tasha paid $20,000,00 for 800 chairs for her restaurant. How much did tasha pay for each chair.

Answers

Answer 1

Answer: 20,000.00/800=$25 dollars per chair I believe

Answer 2

Answer: if there are 800 chairs and she pallid 20000 for all of them then she would have paid 25$per chair

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8/10 divided by 1 5/6

in Farm A, 4/5 of the number of sheep are equal to 1/2 of the number of sheep in farm B. The total number of sheep in farm A and farm B is 845. How many sheep are there in Farm B?

Answers

I believe if I have done this right the answer will be 1352

How do I right 0.389 in expanded form

Answers

0.389= (3x1/10)+(8x1/100)+(9x1/1,000=

10.5 equal or less than 10.005

Answers

10.5 is more than 10.005

HELP PLEASE I WILL GIVE BEST ANSWERAngela is studying two types of birds. She measures the wingspan, in inches, of five Type 1 birds and five Type 2 birds.

What can she infer about the wingspans of the two types of birds?

Type 1: {18, 24, 20, 22, 26}
Type 2: {24, 21, 19, 26, 30}

A.
Type 1 and Type 2 birds have similar wingspan distributions.

B.
Type 1 and Type 2 birds have somewhat similar wingspan distributions.

C.
Type 1 birds and Type 2 birds do not have similar wingspan distributions.

D.
Type 1 birds and Type 2 birds have identical wingspan distributions.

Answers

Answer:

Step-by-step explanation:

The given data set for type 1 of birds is:

Type 1: {18, 24, 20, 22, 26}

Type 2: {24, 21, 19, 26, 30}

Mean of the type 1 data is:

$Mean=(18+24+20+22+26)/(5)=(110)/(5)=22$

Data $(x-{\overline{x})^2$

18 16

24 4

20 4

22 0

26 16

Now, mean average of squares is:

$m=(40)/(5)=8$

Standard deviation= $SD=√(8)=2.828$

Now, the difference of mean and its standard deviation of type 1 data set is:

=22-2.828

Difference =19.172

The given data set for type 2 of birds is:

Type 2: {24, 21, 19, 26, 30}

Mean of the type 2 data is:

$Mean=(24+21+19+26+30)/(5)=(120)/(5)=24$

Data $(x-{\overline{x})^2$

24 0

21 9

19 25

26 4

30 36

Now, mean average of squares is:

$m=(74)/(5)$

$m=14.8$

Standard deviation= $SD=√(14.8)=3.84$

Now, the difference of mean and its standard deviation of type 2 data set is:

=24-3.84

Difference=20.16

Since, the difference of mean and standard deviation of both type 1 and type 2 data set is different, therefore, Type 1 birds and Type 2 birds do not have similar wingspan distributions.

Hence, option C is correct.

Answer:

Type 1 and Type 2 birds have similar wingspan distributions.

Step-by-step explanation:

The answer? i don’t understand this.

Answers

You are simplifying the equation by plugging the numbers in.
$10 * 5 + \frac{ {4}^(2) }{4}$
10•5=50,
$4 {}^(2) + 16$
$50 + (16)/(4)$
$(16)/(4) = 4$
50+4=54

The answer is 54

How can you figure someone age for exampleEvelyn was 9 when her brother Victor was born. Which equation tells you how to find Evelyn's age if you know Victor's age?

e=Evelyn's age
v=victor's age

A. e=v+9
B. v=e+9
C. e=v-9
D. e+v=9

Answers

Since e represents evelyn ege, hence the equation that tells you how to find Evelyn's age if you know Victor's age is e = v + 9

System of equations

These are equation containing unknown variables

If Evelyn was 9 when her brother Victor was born, hence;

Victors age = v

Evelyn age = v + 9

Substitute both equations

Since e represents evelyn ege, hence the equation that tells you how to find Evelyn's age if you know Victor's age is e = v + 9

Learn more on equation here: brainly.com/question/2972832

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A. e=v+9 because if Victor is 6 then it would be 6+9= 15 (Evelyn's Age)

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