1st term = a(1) = -7(1)-1 = -7-1 = -8
2nd term = a(2) = -7(2)-1 = -14-1 = -15
3rd term = a(3) = -7(3)-1 = -21-1 = -22
term would be -8, -15, -22
B.40
C.1980
D.1040
B has a savings account, into which he must deposit $40 each month.
Interest is frequently calculated as an annual percentage of the amount borrowed. This percentage represents the loan's interest rate. For instance, a bank will pay interest if you deposit money in a high-yield savings account.
From the time he was 11 to the time he was 18, Luke's parents saved for him for 8 years, or 8 years x 12 months every year, or 96 months.
Since they were saving $125 per month throughout this time, Luke had amassed the following sum:
$125/month x 96 months = $12,000
Luke must still pay the following expenses because he needs $12,480 for his first year of technological school:
$12,480 - $12,000 = $480
If he has one year left to save this amount, he will need to save:
$480÷12months = $40per month
Therefore, the answer is B. $40.
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look at the first number after the decimal point that isn't a zero.
0.09502 would be 0.01
Answer: The correct option is A.
Step-by-step explanation: We are given a polynomial which is a sum of other 2 polynomials.
We are given the resultant polynomial which is :
One of the polynomial which are added up is :
Let the other polynomial be 'x'
According to the question:
Solving the like terms in above equation we get:
Hence, the correct option is A.
Answer:
6d5 – 2c3d2 + 5c2d3 – 12cd4 + 8