1. Calculate the amount of heat required for 25.0 grams of water tochange from 10 degrees Celsius to 30 degrees Celsius. 2. 50.0 grams of water at 100 degrees Celsius evaporated to water vapor 2 points
at 100 degrees Celsius. Calculate the amount of heat required for this
conversion.

3. A student measured 15.0 grams of ice in a beaker. The beaker was then
placed on a hot plate where it was heated uniformly for a certain amount
of time. During the melting process of the ice, the student noted that the
temperature was at 0 degree Celsius. When all the ice converted to water,
the final temperature was also at 0 degree Celsius. How much heat was
used to melt the ice?

4. If 5.0 grams of water was cooled from 50 degrees Celsius to 40
degrees Celsius, then calculate the amount of heat released by the water.

5. A certain amount of water used exactly 84.0 Joules of heat energy to
change from 25.0 degrees Celsius to 35 degrees Celsius. How many
grams of water was used?


Please help me

Answers

Answer 1
Answer:

Answer:

Explanation:

1 )

amount of heat required = mass x specific heat x rise in temperature

= 25 x 4.2 x 20 = 2100 J .

2 )

Amount of heat required

= mass x latent heat of vaporisation

= 50 x 2260 = 113000 J  .

3 )

Amount of heat required in melting the ice

= mass x latent heat of fusion

= 15 x 336 = 5040 J

4)

heat released in cooling water

= mass x specific heat x fall in temperature

= 5 x 4.2 x 10

= 210 J

5 )

amount of heat required = mass x specific heat x rise in temperature

84 = mass x 4.2 x 10

mass = 2 grams .


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Which equations shows the complete dissociation of a strong base? HCl -> cl- + H+

HNO2 -> H+ + NO2-

HA + h20 -> A- + H+ + h20

BOH + h20 -> B+ + OH- + H20

Answers

The correct answer is the fourth option. The complete dissociation of a strong base is BOH + h20 -> B+ + OH- + H20 since this is the only base from the choices given. A base is a substance that accepts hydrogen ions. 

Answer : The correct option is, (4) BOH+H_20\rightarrow B^++OH^-+H_20

Explanation :

Strong acid : Strong acids are those acids which are completely dissociates into ions in water. It dissociates into hydrogen ion and an anion.

Strong base : Strong base are those base which are completely dissociates into ions in water. It dissociates into hydroxide ion and a cation.

In all the given options, option (4) BOH+H_20\rightarrow B^++OH^-+H_20 equation shows the complete dissociation of a strong base.

While the other options shows the complete dissociation of an acid.

Imagine that an uncharged pith ball is brought into the electrostatic field of a charged tod. The side of the pith ball closest to the negatively charged end of the rod will

Answers

When an uncharged pith ball is brought into the electrostatic field of a charged tod, the side of the pith ball closest to the negatively charged end of the rod will also gain a negatively charged surface. Then, it will not attract to the charged tod but rather it will repel.

I need the answer asap

A solution is made by dissolving 54.0 g of silver nitrate in enough water to make 350.0 ml. A 10.00 ml portion of this solution is then diluted to a final volume of 250.0 ml. What is the total concentration of ions present in the final solution?

Answers

Answer:

  • 0.0726 M

Explanation:

Molar concentration of the final solution is the number of moles of solute (n) divided by the final volume in liters (V). This is the mathematical formula for molarity:

M = n solute / V solution in liters = n silver nitrate / V solution in liters

1) Calculate the number of moles of silver nitrate in the initial solution, dissolving 54.0 g of silver nitrate to make 350.0 ml of solution:

  • Solute = silver nitrate = AgNO₃

  • Molar mass of AgNO₃ = 169.87 g/mol

  • n = mass in grams / molar mass = 54.0 g / 169.87 g/mol = 0.318 mol

2) Calculate the molarity of the initial solution:

  • M = n / V = 0.318 mol / 0.3500 liter = 0.9086 M

3) Calculate the number of moles of silver nitrate in a 10.0 ml portion of that solution:

  • M = n / V ⇒n = M × V

 

         n = 0.9086 M × 10.0 ml / (1,000 ml / liter) = 0.009086 moles silver nitrate

4) Molar concentration (molarity) of the final 250.0 ml solution:

  • M = n / V = 0.009086 mol / 0.2500 liter = 0.0363 M

5) Concentration of ions present in the final solution:

You must assume 100% ionization:

  • AgNO₃ → Ag⁺ + NO₃⁻

Then, since each mole of AgNO₃ yields two moles of ions, the total concentration of ions present is the double: 2 × 0.0363 M = 0.0726 M

All of the following are abiotic factors in an ecosystem except nutrients

sunlight

rain

bacteria

Answers

Answer:

The correct answer is option d: bacteria

Explanation:

Hello! Let's solve this!

Abiotic components are those that have no life and biotics are the factors that have life.

Let's see each option!

Nutrients: they have no life, they can be calcium, protasium, vitamins

sunlight: it has no life, it comes from the sun

rain: it has no life, it is condensed water and it falls to the earth in the form of drops

bacteria: they have life, they are cells so they are living beings.

We conclude that the correct answer is option d: bacteria

Bacteria are the living/biotic components in an ecosystem.

How many kilojoules are equivalent to 10 joules?

Answers

1 Kj ------------- 1000 J
?? --------------- 10 J

10 x 1 / 1000 => 0.01 Kj

2NaCl + H2SO4 --> 2HCl + Na2SO4How many grams of HCl can be prepared from 2.00 mol H2SO4 and 2.56 mol NaCl?

a. 7.30 g
b. 93.3 g
c. 146 g
d. 150 g
e. 196 g

Answers

\frac{2.00}1=2.00,(2.56)/(2)=1.28<2.00 hence NaCl is the limiting reagant.

One mole of NaCl yields one mole of HCl, hence we'll make at most 2.56*(1.00+35.5)=93.4g

That would be answer B (the difference probably comes from the molar mass of Cl that I chose, 35.5, whereas some prefer to take 35.4)

Final answer:

The question tackles stoichiometry, a Chemistry concept used to calculate reactant or product amount. Given 2 moles of H2SO4 and 2.56 moles of NaCl, the H2SO4 is limited, resulting in 4 moles of HCl. The weight of 4 moles of HCl is 146 g, thus, the answer is c. 146 g.

Explanation:

The subject of this question is stoichiometry, a method used in Chemistry to calculate the amount of reactants or products in a particular chemical reaction. According to the balanced equation, 2 moles of NaCl react with 1 mole H2SO4 to yield 2 moles of HCl. Meaning, 1 mole of H2SO4 can only react effectively with 2 moles NaCl. However, we have 2.56 mol of NaCl. This means that the H2SO4 is the limiting reagent. Thus, 2 mol H2SO4 will yield 4 mol of HCl (since it's 2:2 ratio).
The molecular weight of HCl is 36.5 g/mol. Therefore, the weight of 4 moles of HCl is 4 mol * 36.5 g/mol = 146 g. Thus, the correct answer is c. 146 g.

Learn more about Stoichiometry here:

brainly.com/question/30218216

#SPJ11

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