Answer:
Q = 836 J
Explanation:
Given data:
Mass of water = 10.0 g
Temperature increased =ΔT = 20°C
Specific heat capacity of water = 4.18 J/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Q = 10.0 g × 4.18 J/g.°C × 20°C
Q = 836 J
The mass percent of hydrogen in diethyl ether is 1.36%.
To calculate the mass percent of hydrogen in diethyl ether, we need to determine the mass of hydrogen in the compound and divide it by the total mass of diethyl ether. The formula of diethyl ether is C4H10O, so the molar mass is 74.12 g/mol. The molar mass of hydrogen is 1.008 g/mol.
Mass percent of hydrogen = (mass of hydrogen / mass of diethyl ether) × 100%
Mass percent of hydrogen = (1.008 g/mol / 74.12 g/mol) × 100% = 1.36%
#SPJ2
Ah yes.
The atomic radius is basically the distance between the nucleus of the atom and the outermost electron in the farthest orbital of the atom. The more bigger the atomic radius , the less powerful is the force that holds together the nucleus and its electrons.
Answer:
FeO(s)+2NaCL(aq)>FeCL2(aq)+Na2O(s)
2 moles of sodium chloride react with 1 mole of iron (II) oxide to give 1 mole of iron (II) chlorine
mole ratio NaCl :FeCl=2:1
mass of FeCl=0.5×450=225g
Explanation:
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Answer:
5 pumpkin pies could be made with 7.5 cups of sugar.
Explanation:
The conversion factor to solve the problem is:
(2) molecular masses
(3) numbers of covalent bonds
(4) percent compositions by mass
Answer:
approximately 4.8 grams of oxygen gas is formed.
Explanation:
To determine the amount of oxygen (O2) formed when 12.26 grams of potassium chlorate (KClO3) is heated, we need to consider the chemical reaction that occurs during this process. When KClO3 is heated, it decomposes into potassium chloride (KCl) and oxygen gas (O2).
The balanced chemical equation for this reaction is:
2 KClO3(s) → 2 KCl(s) + 3 O2(g)
From the equation, we can see that 2 moles of KClO3 produce 3 moles of O2.
Calculate the molar mass of KClO3:
K: 39.10 g/mol
Cl: 35.45 g/mol
O: 16.00 g/mol
Molar mass of KClO3 = (39.10 + 35.45 + 3 * 16.00) g/mol = 122.55 g/mol
Calculate the number of moles of KClO3 in 12.26 grams:
Moles of KClO3 = (12.26 g) / (122.55 g/mol) = 0.1 moles
Now, we can determine the number of moles of O2 produced using the mole ratio from the balanced equation:
Moles of O2 = (0.1 moles of KClO3) * (3 moles of O2 / 2 moles of KClO3) = 0.15 moles
Finally, convert moles of O2 to grams:
Mass of O2 = (0.15 moles) * (32.00 g/mol for O2) = 4.8 grams
So, when 12.26 grams of KClO3 is heated, approximately 4.8 grams of oxygen gas is formed.