MATHEMATICS HIGH SCHOOL

Select all ratios that are in their simplest form.
4:24 28:15 3:13 18:30 12:14

Answers

Answer 1
Answer:

Answer:

1. 28:15

2. 3:13

Step-by-step explanation:

The ratios above have no common factor.

4:24 .

Common factor : 4

18:30

Common factor : 6

12:14

Common factor : 2
Answer 2
Answer:

Answer:

28:15

3:13

Step-by-step explanation:

The ratios 28:15 and 3:13 are in their simplest form, meaning that they cannot be simplified any further.

Meanwhile, the other 3 ratios are not in their simplest form and can still be simplified if they are divided by either 2 or 4.

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"I am an odd number. I am more than 40. I am less than 42. I am ________."

Answers

Final answer:

"I am an odd number. I am more than 40. I am less than 42. I am 41"

Explanation:

This problem can be solved through basic number sense. We are dealing with a specific subset of numbers - odd numbers. We are told that this number is more than 40 and less than 42. Thus, the number we're looking for here is essentially the only odd number that falls between 40 and 42, which is 41.

When you say you are an odd number that is more than 40 and less than 42, there is only one number that fits this criteria: 41. In the range between 40 and 42, the only odd number is 41.

Learn more about Odd Numbers here:

brainly.com/question/240064

#SPJ11
The answer is 41 obviously

what is the multiplicative rate of change of the function shows on the graph? Express your answer in a decimal form round to the nearest tenth. pllzzz the picture is there

Answers

The formula to get the multiplicative rate of change is this:
[ f(x2) / f(x1) ] / (x2 - x1)
or
(y2 / y1) / (x2 - x1)

Choosing of the coordinates (-1, 0.8) and (0,2)
MRC = 2/0.8 / (0-(-1)) = 5/2

Using the other coordinates (0,2) and (1,5)
MRC = 5/2 / (1-0) = 5/2

The MRC will be constant per interval.

Y=8x+168
how do i get the x-intercept and
y-intercept to this equation?

Answers

The x intercept occurs when y=0, and the y intercept when x=0. Substitute these values into the equation to find the intercepts

Which relation is a function?A. {(2, 3), (1, 5), (2, 7)}



B. {(-1, 5), (-2, 6), (-3, 7)}



C. {(11, 9), (11, 5), (9, 3)}



D.{(3, 8), (0, 8), (3, -2)}

Answers

Answer: Option B

Step-by-step explanation:

A function has a rule, for each point in the domain, there can be only one point associated in the range.

This means that f(x) can have only one value y that is associated to the point x in the domain.

now, with this in mind, let's analyze the options, where the pairs are always written as (x, y)

A) Here we can see the pairs (2,3) and (2, 7), so we have the point in the domain, 2, that is associated with two different values in the range, so this relation can not be a function.

B) In this set, there are no problems because we do not have ani point in the domain with more than one value in the range, so this can be a function.

C) here point 11 has two different values in the range, so this can not be a function.

D) here point 3 has two different values in the range, so this can not be a function.
b, because for every one you take away from the x value, you add one to the y value

What is seven point five divided by one hundred

Answers

7.5/100
= 0.075.

The final answer is 0.075~

Circle P
has center
P
(2, 0) and radius 20. Circle
Q
has center
Q
(0, 4) and radius 2.
(a)
Describe the rule for translating center
Q
onto center
P
.
(b)
Determine the scale factor for dilating circle
Q
so that it has the same radius as circle
P.
(c)
Are circles
P
and
Q
similar? Explain your answer.

Answers

Siras !  Don't try to picture this all in your head !
You'll wear out your brain.
You MUST sketch it on a piece of paper.
Draw an x-axis and a y-axis, then draw the two circles.

I'm drawing myself a picture right now, and I'm
supposed to be some kind of a genius.

a).  In order to move Circle-Q so that both centers are
at the same point, you need to move the center of Q
4 units down and 2 units to the right.
      When you do that, you'll have the little circle inside the
big circle, with their centers both at the same place.

b).  The radius of Q is 2.
       The radius of P is 20.
       What do you have to multiply 2 by, in order to get 20 ?
       THAT's the scale factor to dilate Q so that it has the same
radius as P.
       When you do that, suddenly it'll look like you only have one circle
on the paper ... they'll both have the same radius and their centers are
at the same place, so you can't tell them apart.

c).  All circles are similar !

I went online (you could easily go there too).  I searched the question
"Are circles similar ?" and a lot of interesting stuff came up.  (you could
do that too).  I saw a lot of ways to prove that all circles are similar. 
The best one says:

       Two figures are "similar" if you can make one of them
       exactly fit on top of the other one (make them congruent)
       with translations and dilations.

You just did that with P and Q !

-- Translation is moving them around.
   You moved Q and put the centers of both circles at the same place.

-- Dilation is blowing it up or blowing it down, so its size changes
but its shape doesn't change.
   You blew Q up so that it had the same radius as P.
   Then the two circles exactly fit over/under each other.

So the two circles are similar. 
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