30. What is the degree of the polynomial?31. Which polynomial is in descending order in terms of x?

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30. What is the degree of the polynomial? 31. Which - 1

Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

30). 5^(th) degree ( 4 + 1 = 5 ; 1 + 1 = 2 and 2 + 2 = 4 )

31) D) Choice D


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Clare bought an expensive for £38 000 and sold it 3 years laterfor £25 000. Find the percentage lossthat she made on the sale. (1 dp)
ANSWER ASAP IM BEING TIMEDWILL GIVE BRAINLIEST IF UR CORRECT AND IF I GET AN A ILL DO A FREE POINT GIVEAWAY Choose the polynomial written in standard form. xy2 + 4x4y + 10x2 x4y2 + 4x3y + 10x x4y2 + 4x3y5 + 10x2 x6y2 + 4x3y8 + 10x
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Add the numbers in the series 3+11+19+27+.....+395+403.

Answers

Answer:

10353

Step-by-step explanation:

The given series is in arithmetic progression since the common difference is same which is 8.

To find the sum of series we can simply apply the formula'

S= n/2( first term + last term)

S is the sum and n is the number of terms

we also need to find the number of terms n

n = (last term- first term)/2 + 1

n= (403-3)/(8) + 1

n= 51

s= (51)/(2)(3+403)

s= 10353

Solve used the basic percent equation 10% of 600 is what ??? Remember Percent×base=amount

Answers

Your answer is 60 because you multiply 600 with .10 and get 60.00
10%=0.1
0.1×600=60
10% of 60 is 60

Heights of women (in inches) are approximately N(64.5,2.5) distributed. Compute the probability that the average height of 25 randomly selected women will be bigger than 66 inches.

Answers

Answer:

the probability that the average height of 25 randomly selected women will be bigger than 66 inches is 0.0013

Step-by-step explanation:

From the summary of the given statistical dataset

The mean and standard deviation for the sampling distribution of sample mean of 25 randomly selected women can be calculated as follows:

\mu_(\overline x) = \mu _x = 64.5

\sigma_(\overline x )= (\sigma)/(\sqrt n)

\sigma_(\overline x )= \frac{2.5}{\sqrt {25}}

\sigma_(\overline x )= (2.5)/(5)

\sigma_(\overline x ) = 0.5

Thus X \sim N (64.5,0.5)

Therefore, the probability that the average height of 25 randomly selected women will be bigger than 66 inches is:

P(\overline X > 66) = P ( (\overline X - \mu_\overline x)/(\sigma \overline x )>(66 - 64.5)/(0.5) })

P(\overline X > 66) = P ( Z>(66 - 64.5)/(0.5) })

P(\overline X > 66) = P ( Z>(1.5)/(0.5) })

P(\overline X > 66) = P ( Z>3 })

P(\overline X > 66) = 1- P ( Z<3 })

P(\overline X > 66) = 1- 0.9987

P(\overline X > 66) =0.0013

the probability that the average height of 25 randomly selected women will be bigger than 66 inches is 0.0013

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Answers

Answer:

1) 1050 ft squared

2) 200 yards

Step-by-step explanation:

Hope this helps! Pls give brainliest!

Emma uses 250 centimeters of crepe paper to make streamers. How many meters did Emma use

Answers

Answer:

2.5

Step-by-step explanation:

250 cm equals 2.5 m

Answer:

25 is what I got

Organizers of an outdoor summer concert in Toronto are concerned about the weather conditions on the day of the concert. They will make a profit of $31,000 on a clear day and $10,000 on a cloudy day. They will make a loss of $5,000 if it rains. The weather channel has predicted a 47% chance of rain on the day of the concert. Calculate the expected profit from the concert if the likelihood is 14% that it will be sunny and 39% that it will be cloudy.

Answers

Answer: Expected profit is $5,750

Step-by-step explanation:

Given data:

Profit on clear day = $30,000

Profit on a cloudy day = $10,000

Loss when it rains = $5,000

Likelihood = 14%

Sunny = 39%

Solution

First we apply the Expected profit formula

= (30,000*0.14)+(10,000*0.39)+(-5000*0.47)

= $4200 + $3900 + ($2350)

= $8100 + ($2350)

= $5,750

The calculated expected profit is $5,750.