Boris buys candy that costs $7 per pound. He will spend at least $63 on candy. What are the possible numbers of pounds he will buy?

Answers

Answer 1
Answer:

Answer:

Anything above 9

Step-by-step explanation:

63/7=9


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Urgent can you help right away! Please help with these math questions!!!!
Answer 1 and 2 in hundredths and 3 in tenths

Answers

A
R=8 km
B
r= 7ft
h = 11ft
C
r= 10 mi
h = 20 mi

Identify m∠C in the triangle shown.Question 6 options:

A)

17°

B)

23°

C)

21°

D)

19°

Answers

Answer:

C

Step-by-step explanation:

Answer: 21

Answer:

c

Step-by-step explanation:

8/t + t^2; t=4 please help me

Answers

Answer:

8/t + t^2 = 18

Step-by-step explanation:

8/t + t^2

t = 4

8/4 + 4^2

2 + 16 = 18

8/t + t^2 = 18

19) Solve the system,
*****
x + 3y - 5
-2x + 2y = 14

Answers

Answer:

y = 3

x = -4

Step-by-step explanation:

Hopefully the first equation is x + 3y = 5

x = 5 - 3y

Plug in:

-2(5 - 3y) + 2y = 14

-10 + 6y + 2y = 14

8y = 24

y = 3

x = -4

A polynomial multiples by a polynomial is a polynomial

Answers

A polynomial multiple by a polynomial is always a polynomial. The given statement is true.

What are polynomials?

Polynomials are those algebraic expressions that consist of variables, coefficients, and constants. The standard form of polynomials has mathematical operations such as addition, subtraction, and multiplication.

When two polynomials are multiplied by each other, then each term of the first polynomial is multiplied by each term of the second polynomial.

The result is always a polynomial, regardless of what the coefficients might be of any of the terms, including the leading coefficients.

Thus, A polynomial multiples by a polynomial is always a polynomial.

Learn more about polynomials;

brainly.com/question/11536910

When two polynomials are multiplied, each term of the first polynomial is multiplied by each term of the second polynomial. ... The result is always a polynomial, regardless what the coefficients might be of any of the terms, including the leading coefficients.

Find an equation for the tangent to the curve at P and the horizontal tangent to the curve at Q. y = 5 + cot x - 2 csc x 0 1 2 3 0 2 4 x y Upper QUpper P left parenthesis StartFraction pi Over 2 EndFraction comma 3 right parenthesis

Answers

Answer with explanation:

The given function in x and y is,

  y= 5 +cot x-2 Cosec x

To find the equation of tangent, we will differentiate the function with respect to x

y'= -\csc^2 x+2 \csc x* \cot x

Slope of tangent at (π/2,3)

 y'_{((\pi)/(2),3)}= -\csc^2(\pi)/(2) +2 \csc (\pi)/(2)* \cot (\pi)/(2)\n\n=-1+2* 1 * 0\n\n= -1

Equation of tangent passing through (π/2,3) can be obtained by

\rightarrow (y-y_(1))/(x-x_(1))=m(\text{Slope})\n\n \rightarrow (y-3)/(x-(\pi)/(2))=-1\n\n\rightarrow 3-y=x-(\pi)/(2)\n\n\rightarrow x+y-3-(\pi)/(2)=0

⇒There will be no Horizontal tangent from the point(π/2,3).