in 2005 a company spent 493,749,335 on advertising. round the advertising figure to the nearest hundred thousand.​

Answers

Answer 1
Answer:

Answer: 493,700,000

Step-by-step explanation:


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Help Please I really need help!

Answers

400+60x

because the flat rate will stay the same, depending on how many hours or labor is how much more money you will pay. 60 dollars per hour of labor

Evaluate √-75 where s = -3
PLS I NEED HELP ASAP!!!!

Answers

What math are you in like th

What is 75miles/hr in feet/second?(1mile = 5280feet)

Answers

Answer:

110 feet/sec

Step-by-step explanation:

75 miles x 5280 feet

= 396000

396000/60 min

=6600

6600/60 secs

=110 feet/second

Rectangle J'K'L'M' shown on the grid is the image of rectangle JKLM after transformation. The same transformation will be applied on trapezoid STUV.Rectangle JKLM is drawn on the grid with vertices J at negative 8, negative 8, K at negative 4, negative 8, L at negative 4, ne

What will be the location of T' in the image trapezoid S'T'U'V'? (1 point)

(12, 6)
(12, 7)
(16, 7)
(16, 6)

Answers

Answer:

  • (16, 7)

Step-by-step explanation:

Given rectangle JKLM

As per graph, the rectangle J'K'L'M' is the transformation of JKLM

Based on one of the points we can calculate the transformation rule:

Let's use points K and K'

  • K((-4, -8) → K'(6, -5)
  • 6 - (-4) = 10
  • -5 - (-8) = 3

So the rule is

  • (x', y') → (x + 10, y +3)

Trapezoid STUV:

  • Using point T(6, 4)

Applying same rule:

  • T' = (6 + 10, 4 +3) = (16, 7)

Answer: its c (16, 7)

i just took the test and got it right

Find the scale.


Model length: 40 cm


Actual length: 60 m

Answers

Answer:

2/3

Step-by-step explanation:

Given

Model length: 40 cm

Actual length: 60 m

Scale for any model is ratio of model length of object and actual length of object

Therefore scale for problem stated = Model length/Actual length

= 40/60 = 4/6 = 2/3

Use the compound interest formulas A = P 1 + r n nt and A = Pe rt to solve. 2) Suppose that you have $8000 to invest. Which investment yields the greater return over 6 years: 6.25% compounded continuously or 6.3% compounded semiannually? 2) A) $8000 invested at 6.3% compounded semiannually over 6 years yields the greater return. B) $8000 invested at 6.25% compounded continuously over 6 years yields the greater return. C) Both investment plans yield the same return.

Answers

Answer: A

Compound interest simply defined as the interest added at regular interval. Compound interested can be calculated using

Compound interest = P (1+) ^nt and Pe ^rt

P = Initial balance

r = Annual interest rate

n = Number of times the interest is compounded per year

t =Number of year money is invested

Using

Compound interest = P (1+ ) ^nt

Continuous

P= $ 8000

t = 6

r = 6.25%

=

= 0.0625

n = 1

Compound interest = 8000 (1+) ^1×6

= 8000 (1 + 0.0625) ^6

= 8000 (1.0625) ^ 6

= 8000× 1.4387

= $11,509.6

Semi- annually

P= $ 8000

t = 6

r = 6.3%

=

= 0.063

n = 2

Compound interest = 8000 (1+) ^2×6

= 8000 (1 + 0.063) ^12

= 8000 (1.063) ^12

= 8000× 1.4509

= $11,607.0

Investing $ 8000 semi-annually at 6.3% for 6 years yields greater return

Therefore the answer is (A)