Answer:
The first four terms of the sequence are: {-10,-23,-62,-179}
Step-by-step explanation:
Given recursive formula is:
First term = a1 = -10
The first term is already known. In order to find the next terms, we will put n=2,3,4 in the recursive formula.
Putting n=2
Putting n=3
Putting n=4
Hence,
The first four terms of the sequence are: {-10,-23,-62,-179}
Answer:
Let fertilizer be F
and peat moss be P
since F is proportional to P
F = kP
where, k = constant of proportionality
k = F/P
putting in the values,
k = (3/4) /12
k = 3/4 * 1/12
k = 1/16
Therefore the constant of proportionality is 1/16.
To find the value of z such that 0.11 of the area lies to the right of z, use the standard normal probability table. The value of z is approximately 1.96.
To find the value of z such that 0.11 of the area lies to the right of z, we can use the standard normal probability table. The area to the right of z is equal to 1 minus the area to the left of z.
Using the information given, the area to the left of z that corresponds to a value of 0.025 is 0.975. The area to the left of 1.96, which can be found using the standard normal probability table, is 0.975.
Therefore, the value of z is approximately 1.96.
#SPJ11
Answer:
1.23?
Step-by-step explanation:
Answer:
8000<x<80000
Step-by-step explanation:
a number(x) is greater than (<) 8000
and x is also less than(<) 80000
Answer:
71.63 kilowatts hours
Step-by-step explanation:
We are told in the question:
John's electricity bill costs $20.90 per month plus $1.23 per kilowatt hour.
We are to find, How many kilowatt hours can he use and keep his monthly cost no more than $109.
Step 1
$109 - $20.90
= $88.1
$88.1 is the amount left to spend on killowatts of electricity per hour after removing the normal monthly electricity bill in a month
Step 2
$1.23 = 1kilowatts per hour
$88.1 = y kilowatts per hour
Cross Multiply
= $1.23 × y kilowatts per hour = $88.1 × 1 kilowatts per hour
y kilowatts per hour = $88.1 × 1 kilowatts per hour/ $1.23
= 71.62601626kilowatts hour.
Approximately = 71.63 kilowatts hour
Therefore, John can use 71.63 kilowatts per hour and keep his monthly cost no more than $109
Answer:
71
kilowatt hours can he use and keep his monthly cost no more than $109