, and the chemical formula of the compound is
Answer:
a) oxidation number of chromium is +3
b) formula of the compound is Cr2(SO4)3
Explanation:
From the name of the compound, we can see that the oxidation state of chromium is +3
We know the sulphate ion to to be SO4^2-
According to the rules of writing the formula of compounds from valencies, the valency of chromium is 3 while that is the sulphate ion is 2.
The both species can now exchange valency
Cr2(SO4)3------- This is the correct formula of the compound
Answer:
The oxidation state is +3.
chemical formula of compound is Cr₂(SO₄)₃.
Explanation:
Calculation of oxidation state:
Cr₂(SO₄)₃
Cr= ?
The oxidation state of SO₄ = -2
2x + 3( -2) = 0
2x - 6 = 0
2x = 6
x = 6/2
x= 3
The oxidation state of Cr is +3.
The Cr has valency of 3 so three SO₄ will require while the valency of SO₄ is 2 so two Cr will require.
Cr×2 and SO₄×3
Cr₂(SO₄)₃
we know that oxidation state of Cr is +3 so (3×2) = 6
and the oxidation state of SO₄ is -2 so (-2× 3) = -6
6-6= 0
The overall charge is 0, the compound will be neutral.
Answer:BaCl2 + Al2(SO4)3 -->BaSO4 + AlCl3.
Explanation:
Answer:For Fe
Z=26
Explanation:
1s2 2s2 2p6 3s2 3p6 4s2 3d6
Are there 26 electrons here? Why should there be 26?
So going back to the inert gas, argon ( Z=18 ), we get
[Ar] 4s2 3d6
Make sure to check your work by counting the electrons you have