60 − (7 + 4) × 5 what is the answer

Answers

Answer 1
Answer:

Answer:

5

Step-by-step explanation:

Answer 2
Answer:

Answer:

80

Step-by-step explanation:

because 7+4=28 x 5 =140-60=80


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Find the measure of AB *

14 cm
24 cm
10 cm
140 cm

Answers

Answer:

10 cm

Step-by-step explanation:

Because it is a parrallogram and by its property it will be 10

During the period of time that a local university takes phone-in registrations, calls come inat the rate of one every two minutes.
a. What is the expected number of calls in one hour?
b. What is the probability of three calls in five minutes?
c. What is the probability of no calls in a five-minute period?

Answers

Answer:

a) The expected number of calls in one hour is 30.

b) There is a 21.38% probability of three calls in five minutes.

c) There is an 8.2% probability of no calls in a five minute period.

Step-by-step explanation:

In problems that we only have the mean during a time period can be solved by the Poisson probability distribution.

Poisson probability distribution

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

a. What is the expected number of calls in one hour?

Calls come in at the rate of one each two minutes. There are 60 minutes in one hour. This means that the expected number of calls in one hour is 30.

b. What is the probability of three calls in five minutes?

Calls come in at the rate of one each two minutes. So in five minutes, 2.5 calls are expected, which means that \mu = 2.5. We want to find P(X = 3).

P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)

P(X = 3) = (e^(-2.5)*(2.5)^(3))/((3)!) = 0.2138

There is a 21.38% probability of three calls in five minutes.

c. What is the probability of no calls in a five-minute period?

This is P(X = 0) with \mu = 2.5.

P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)

P(X = 0) = (e^(-2.5)*(2.5)^(0))/((0)!) = 0.0820

There is an 8.2% probability of no calls in a five minute period.

how can you determine that the polynomial function does not have any zeros with even Multiplicity? Explain.​

Answers

Answer:

See Below.

Step-by-step explanation:

Remember multiplicity rules:

  • If a factor has an odd multiplicity (e.g. 1, 3, 5...), then the graph will cross the x-axis at that point.
  • If a factor has an even multiplicity (e.g. 2, 4, 6...), then the graph will bounce off the x-axis at that point.

From the graph, we can see that at our zeros, the graph always passes through the x-axis.

Hence, we do not have any zeros with even multiplicity since the graph does not "bounce" at any of the zeros.

Final answer:

To determine if a polynomial function has zeros with even multiplicity, examine the graph or the exponents of the factors in the function. If there are no real zeros or all the factors are raised to odd powers, there won't be any even multiplicity zeros.

Explanation:

In order to determine if a polynomial function has zeros with even multiplicity, we can examine the function's graph. If a polynomial function does not have any real zeros, then it does not have any zeros with even multiplicity. This is because even multiplicity zeros occur when a factor appears multiple times in the function. However, if all the factors are raised to odd powers, then there won't be any even multiplicity zeros. On the other hand, if the function does have real zeros, we can look at the graph of the function to check if any zeros occur with even multiplicity.

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Evaluate the expression 3.14(a2 + ab) when a = 3 and b = 4.

Answers

Answer:

65.94

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Step-by-step explanation:

Step 1: Define

Identify

3.14(a² + ab)

a = 3

b = 4

Step 2: Evaluate

  1. Substitute in variables:                                                                                     3.14(3² + 3 · 4)
  2. (Parenthesis) Exponents:                                                                                 3.14(9 + 3 · 4)
  3. (Parenthesis) Multiply:                                                                                      3.14(9 + 12)
  4. (Parenthesis) Add:                                                                                            3.14(21)
  5. Multiply:                                                                                                             65.94

Hey there!

3.14(a^2 + ab)

= 3.14(3^2 + 3 *4)

3^2

= 3 * 3

= 9

3 * 4

= 12

3.14(9 + 12)

9 + 12

= 21

3.14(21)

= 65.94

Answer: 65.94

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Rewrite the expression as a product using GCF and distributive property= 27+45= Explain your answer.

Answers

Step-by-step explanation:

The greatest common factor (GCF) of 27 and 45 is 9.

27 + 45

9 (3 + 5)

9 (8)

72

Final answer:

The expression 27 + 45 is rewritten using the Greatest Common Factor (GCF) and the distributive property as 9*(3 + 5) = 72.

Explanation:

The given expression is 27 + 45. To rewrite this using the Greatest Common Factor (GCF) and the distributive property, we first find the GCF of the two numbers. The GCF of 27 and 45 is 9. We then divide each number by the GCF and rewrite the expression using the distributive property.

So, 27 + 45 = 9*(3 + 5) = 9*8 = 72.

The above step is the application of the distributive property, where a*(b + c) = ab + ac.

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A tank contains 22 gallons of water when all of a sudden the water begins draining at a constant rate of 2 gallons per hour. Let t represent the number of hours since the water begun draining and let v represent the volume of water in the tank. Write a formula that expresses y in terms of t .

Answers

Answer:

V= 22-2t

Step-by-step explanation:

I guess the alphabet should be v instead of y. So I am working using v

The rate at which water is draining from the tank is 2gallons/hour. This is the rate of water removal from the tank. So after an hour, 2 × 1= 2 gallons would have drained. After 5 hours, 2×5 =10 gallons would have drained

Therefore to obtain the amount of water in gallons that have been removed from the tank, you will multiply the rate by the time in hours after which the draining started.

Amount (gallons) =2×t

The amount of water remaining in the tank will be obtained by subtracting the amount of water drained after some hour (2×t) from the initial amount of water in the tank (22)

Therefore, the amount of water present in the tank (v)= 22-2t or 2(11-t) gallons

Final answer:

The formula to express volume of the water v in terms of time t is v = 22 - 2t, where 22 is the initial volume and 2t represents the rate at which the water is draining.

Explanation:

This problem is a mathematical representation of a real-world scenario using a linear equation. The volume of water v in the tank can be represented in terms of time t through the equation v = 22 - 2t. This equation illustrates the initial volume of water in the tank (22 gallons) and accounts for the constant rate at which the water is draining (2 gallons per hour).

When time t = 0 (meaning no time has passed since the water started draining), the volume of water v = 22 (the initial volume). As time increases, the volume gradually decreases at a rate of 2 gallons per hour, represented by the term -2t.

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