B. Y=1/2. Y•15; 12/4
C. Y=1/16. Y•15; 15/4
D. Y=1/16. Y•2•15; 12/4
Answer:
Step-by-step explanation:
The equation of the line goes as , where m is slope and b is y-intercept. Since we are already given slope and a point (x,y), we can plug those values in and solve for b.
[multiply]
[add both sides by 20/3]
Now, we can plug in all the values together to get .
The equation of the line with the slope -2/3 that passes through the point (10, -4) is y = -2/3x + 8/3.
The subject of this question is the equation of a straight line, specifically how to write the equation of a line with a given slope and passing through a specific point. Given the slope, m = -2/3, and the point P(10, -4), we can use the point-slope form of the line which is y - y1 = m(x - x1). Substituting the given values into the formula, we get y - (-4) = -2/3(x - 10). Simplifying this we get y + 4 = -2/3x + 20/3. Even further simplification leads to the equation of the line y = -2/3x + 20/3 - 12/3, finall getting y = -2/3x + 8/3.
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What is m∠D
?
Answer:
9.5% decrease
Step-by-step explanation: