Estimate each product 7.1 x 2.1

Answers

Answer 1
Answer:

Answer:

14

Step-by-step explanation:

7.1 rounded is 7

2.1 rounded is 2

so the answer should be 14


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A triangular prism has a base with a height of 5 cm and a base with a width of 4 cm. The prism has a height of 10 cm. What is the volume of the prism?​

Answers

Answer:

The volume of the triangular prism is 100 cubic centimeters.

Consider the function f(x) = (3x-7)/2 with a domain of - ∞ < x < ∞what is the range of f^-1(x) [this is the inverse function]

a. - ∞ <_ x <_ ∞
b. - ∞ < x < ∞
c. - ∞ < f^-1(x) < ∞
d. - ∞ <_ f^-1(x) <_ ∞

please help and thank you!!

Answers

Here we have to use the fact that the domain of the function is equal to the range of the inverse function and range of the function is equal to the domain of the inverse function .

In the given question , the domain of the given function is given. So the range of the given option is same as the domain.

Therefore the correct option is c.

How much is 13 part of 6,918?

Answers

The answer should be 0.19%

On the package for a certain brand of spinach seeds there is a guarantee that, if the printed instructions are followed, of planted seeds will germinate. A random sample of seeds is chosen. If these seeds are planted according to the instructions, find the probability that of them germinate.

Answers

The question is incomplete. Here is the complete question.

On the package for a certain brand of spinach seeds there is a guarantee that, if the printed instructions are followed, 63% of planted seeds will germinate. A random sample of 9 seeds is chosen. If these seeds are planted according to the instructions, find the probability that 4 or 5 of them germinate. Do not round your intermiediate computations, and round your answer to three decimal places.

Answer: P(4<X<5) = 0.624

Step-by-step explanation: The probability of a seed germinate is a BinomialDistribution, i.e., a discrete probability distribution of the number of successes in a sequence of n independents experiments.

This distribution can be approximated to normal distribution by determining the values of mean and standard deviation population:

\mu=np

\sigma=√(np(1-p))

where

n is the sample quantity

p is proportion of successes

For the spinach seeds:

Mean is

\mu=9(0.65)

\mu= 5.85

Standard deviation is

\sigma=√(9.0.65(1-0.65))

\sigma= 1.431

Now, use

z=(x-\mu)/(\sigma)

to convert into a standard normal distribution.

The probability we want is between 2 values: P(4<X<5).

Therefore, we have to convert those two values:

For X = 4:

z=(4-5.85)/(1.431)

z = -1.29

For X = 5:

z=(5-5.85)/(1.431)

z = -0.59

Using z-table:

P(X>4) = 1 - P(z< -1.29) = 0.9015

P(X<5) = P(z< -0.59) = 0.2776

The probability will be

P(4<X<5) = P(X>4) - P(X<5)

P(4<X<5) = 0.9015 - 0.2776

P(4<X<5) = 0.624

The probability of 4 or 5 seeds germinate is0.624.

5.3 divided by 37.63

Answers

7.1 is the correct answer
0.1408450704That is the answer.

In figure, MN : NP = 9:1. If MP = 2. Find the distance from M to point K that is 1/4 the distance from M to N?(A) 1 (B) 1 1/3 (C) 9/20 (D) 1 8/10

Answers

The distance MN is 9/(9+1) = 9/10 of the distance MP, so is

... MN = (9/10)×MP = (9/10)×2 = 9/5

The distance MK is 1/4 that, so is ...

... MK = (1/4)×(9/5) = 9/20 . . . . . matches selection (C)

Answer:

C

Step-by-step explanation:

the answer is C. give the person the brainly :) ignore this answer