MATHEMATICS MIDDLE SCHOOL

what is the slope of the picture (if this is super easy, the reason I asked this question is that my brain is working horrible today)

Answers

Answer 1

Answer:

Answer:3/2 or 1.5

Step-by-step explanation:

(9-6)/(3-1)=

3/2

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Does a polygon usually have more sides or more angles. Explain.

Answers

A polygon should always have the same ratio of sides to angles. Every time you add a side to a polygon, a new angle is created.

Every polygon has the same number of sides as it has angles.

(Their "ratio" is always 1:1 .)

What is the name of the fraction of 7/8

Answers

The numerator in a fraction represents the number of pieces selected. If thenumerator is larger than the denominator, the number is larger than one

The denominator in a fraction represents the total number of equal size pieces thatmake up a whole

7/8 is called a proper fraction.

Which one of the following piecewise graphs is not a function?

Answers

The first graph is not a function because it has two values at x = 3
Definition of a function is that it is a relation that assigns exactly one value for each value in it's domain.

Simplyfi. (9g^10p^8)^2
givin brainlest to first correct

Answers

Answer:

$= 9 {g}^(20) {p}^(16)</p><p>$

hope this helps

brainliest appreciated

good luck! have a nice day!

What is the surface area of the prism? A. 1296 in2
B. 1116 in2
C. 1080 in2
D. 1188 in2

Answers

ok so we have 3 rectangles and 2 triangles
area of rectangle=legnth times width
area of traingle=1/2 times base times height

24 times 20+15 times 20+15 times 20+1/2 times 9 times 24+1/2 times 9 times 24=1296
answer is A

Select the graph of the solution. Click until the correct graph appears. |x|= -5

Answers

graph of |x|=-5 is not possible.

We know that modulus makes everything inside it as positive.

To make the graph of equations with modulus functions, we need to make cases as to check the behavior of the modulus. In this:

CASE-1 :

when expression inside modulus is positive,i.e., x ≥ 0, ∴ |x| = x

Now, |x| = -5

x = -5 ; but we assumed x ≥ 0

So, this case is false.

CASE-2 :

when expression inside modulus is negative,i.e., x < 0, ∴ |x| = -x

Now, |x| = -5

-x = -5

x = 5 ; but we assumed x < 0

So, this case is also false.

In these two cases all the real possible values of x is covered.

Therefore no real value of x satisfies the equation. So, this is false and no graph for it is possible.

Answer:

No Solution

Step-by-step explanation: